java - Android HttpURLConnection写入post数据

Question

我正在尝试通过 HttpURLConnection 发送帖子数据，但它似乎没有发送帖子数据。

我能够在尝试发送 POST 请求之前立即通过 Toast 输出数据，但是当我在服务器端检查时，它会连接到 PHP 文件，但 POST 数据为空。

所以，我知道数据存在于 jsonObject 中。 我也知道它进入了 try catch 语句，但是当我连接时，它没有正确发送或接收。

try {
        URL url = new URL(emailURL);
        HttpURLConnection conn = (HttpURLConnection) url.openConnection();

        conn.setDoOutput(true);

        conn.setRequestMethod( "POST" );
        conn.setRequestProperty( "Content-Type", "application/json");
        conn.setRequestProperty( "charset", "utf-8");
        conn.setRequestProperty( "Content-Length", Integer.toString( jsonObject.toString().length() ));
        conn.setUseCaches( false );

        OutputStreamWriter wr = new OutputStreamWriter(conn.getOutputStream());

        wr.write(jsonObject.toString());

          wr.close();

        BufferedReader reader = null;
        reader = new BufferedReader(new InputStreamReader(conn.getInputStream()));
        StringBuilder sb = new StringBuilder();
        String line = null;

        // Read Server Response
        while ((line = reader.readLine()) != null) {
            // Append server response in string
            sb.append(line + "\n");
        }

        String text = "";
        text = sb.toString();



    } catch (Exception e) {

        throw new RuntimeException(e);
    }

Answer 1

尝试添加方法以确保它确实连接到您的服务器。

修改您的代码，例如:

    int responseCodeFromServer = -1;
    try {
         responseCodeFromServer=conn.getResponseCode();
    } catch (Exception e){
         e.printStackTrace();
    }

    if (responseCodeFromServer == HttpsURLConnection.HTTP_OK){
         BufferedReader reader = null;
         reader = new BufferedReader(new InputStreamReader(conn.getInputStream()));
         StringBuilder sb = new StringBuilder();
        String line = null;

       // Read Server Response
       while ((line = reader.readLine()) != null) {
          // Append server response in string
          sb.append(line + "\n");
       }

       String text = "";
       text = sb.toString();
    }

因此，如果连接到服务器时出现问题，您将看到异常。