jquery - 暂停每个淡入淡出循环

Question

我在 jquery 中有一个 .each 循环，可以淡出图像以在背景中显示它们。每个后续图像都会分配一个增加的延迟。是否可以通过点击来暂停这样的循环？

 <?php
    $ttlart = count($rows);
    echo "var ttlart = " . $ttlart . ";";
    foreach ($rows as $ro) {
        $fadedur = $ro['fadedur'];
            echo "fadedur = " . $fadedur . ";";
            $staysonscreen = $ro['staysonscreen'];
            echo "staysonscreen= " . $staysonscreen . ";";
        $order = $ro['order'];
            echo "order= " . $order. ";";
            echo "$(\"#" . $order . "\").css(\"font-size\",fadedur);";
            echo "$(\"#" . $order . "\").css(\"text-indent\",staysonscreen);";     
            //echo "alert(\"here\");";
    }
    ?>

    var artdelay = 0;
    var playstop = 0;
    var ctr = 1;    

    $($("#images img").get().reverse()).each(function(){
       fadedur = parseInt($(this).css("font-size"));
       staysonscreen = parseInt($(this).css("text-indent"));
       artdelay = artdelay+staysonscreen;

       if (ctr < ttlart){
       $(this).delay(artdelay).fadeOut(fadedur); 
        artdelay = artdelay+fadedur;

      $(".jp-controls").click(function(){

       if(playstop == 0){
       $("#images img").stop(true);
       playstop = 1;
       }else{ //alert(artdelay);
       $("#images img").delay(artdelay).fadeOut(fadedur);
       playstop = 0;}

       });

       ctr=ctr+1;}
    });

Answer 1

您也许可以执行以下操作:

http://jsfiddle.net/EJ6Yg/

$(document).ready(function () {
    var delay = 200;
    $('div').each(function () {
        $(this).delay(delay).fadeOut('slow');
        delay *= 1.5;
    });
});

当然，将 div 替换为图像的一些选择器。

阅读您的更新后，我想我看到了问题 - 您正在使用 delay() 但您希望能够暂停或停止动画。

jQuery API特别提到这一点:

The .delay() method is best for delaying between queued jQuery effects. Because it is limited—it doesn't, for example, offer a way to cancel the delay—.delay() is not a replacement for JavaScript's native setTimeout function, which may be more appropriate for certain use cases.

我相信这是一个 setTimeout 更合适的用例。