google-bigquery - GROUP BY 和 HAVING with ALIAS 的 Bigquery 错误

Question

我注意到 bigquery 标准 sql 中有一个奇怪的错误。
我有一张 table :

SELECT * FROM ds.sod;
| id | name  |
|----+-------|
| 1  | tom   |
| 2  | dick  |
| 3  | harry |

因此，如果我按 exporession 分组它会起作用

SELECT MOD(id,2) AS oddeven, COUNT(1) AS cnt
FROM ds.sod GROUP BY MOD(id,2)
| oddeven | cnt |
+---------+-----+
|       1 |   2 |
|       0 |   1 |

但是如果我添加一个 HAVING 子句，它就会失败。

SELECT MOD(id,2) AS oddeven, COUNT(1) AS cnt
FROM ds.sod GROUP BY MOD(id,2) HAVING COUNT(1) > 0
ERROR: SELECT list expression references column id which is neither grouped nor aggregated

现在奇怪的是，如果我不为列设置别名

SELECT MOD(id,2), COUNT(1) AS cnt
FROM ds.sod GROUP BY MOD(id,2) HAVING COUNT(1) > 0
| f0_ | cnt |
+-----+-----+
|   1 |   2 |
|   0 |   1 |

如果我不使用函数，它也适用于别名

SELECT id AS oddeven, COUNT(1) AS cnt
FROM ds.sod GROUP BY id HAVING COUNT(1) > 1
| oddeven | cnt |
+---------+-----+
|       3 |   1 |
|       2 |   1 |
|       1 |   1 |

难道我做错了什么？或者这是 bigquery 标准 SQL 解析中的错误？

编辑:刚刚注意到如果我按别名分组它确实有效(我从未做过的事情因为在 oracle 7 中不起作用)

SELECT MOD(id,2) AS oddeven, COUNT(1) AS cnt
FROM ds.sod GROUP BY oddeven HAVING COUNT(1) > 0
| oddeven | cnt |
+---------+-----+
|       1 |   2 |
|       0 |   1 |

Answer 1

或者您可以使用列位置

with

sample_data as (
    select
        *
    from
        unnest(
            array[
                struct(1 as id, 'tom' as name),
                struct(2, 'dick'),
                struct(3, 'harry')
            ]
        )
)

select
    mod(id, 2) as oddeven,
    count(*) as cnt
from
    sample_data
group by
    1
having
    count(*) > 0