python:如何在一副牌中生成成对的牌

Question

假设我有以下变量:

suits = ["h","c", "d", "s"]
cards = ["2","3", "4", "5", "6", "7", "8", "9", "t", "j", "q", "k", "a"]
deck = []

for suit in suits:
    for card in cards:
        deck.append(str(card+suit))

我想编写一个函数，在给定特定卡片的情况下，生成可能的配对组合。

例如，generatePairs('a') 应返回如下内容:

['ahac','ahad','ahas','acad','acas','adas']

但我不确定如何编写该函数。

Answer 1

In [7]: import itertools

In [8]: c = 'a'

In [9]: ['%s%s%s%s' % (c, s1, c, s2) for (s1, s2) in itertools.combinations(suits, 2)]
Out[9]: ['ahac', 'ahad', 'ahas', 'acad', 'acas', 'adas']