php - 如何在 Jquery 成功方法中获取 "last inserted id to database "？

Question

嗯，在我的添加联系人表单中，我使用 Jquery 和 Php 将数据插入到 Mysql 数据库。已成功将数据插入数据库。现在我要将成功的页面重定向到 index.php?cdid=$last_id。但是我怎样才能在 jquery success 方法中获得这个 $last_id ？我只能显示成功的消息。有什么帮助吗？

Jquery 代码:

<script>
$('#addcontact').submit(function(event) {
  event.preventDefault();
  $.ajax({
   type: 'POST',
   url: 'add_contact_process.php',
   data: $(this).serialize(),
      dataType: 'json',      

   success: function (data) {
        $('#success').html('');
        $.each( data, function( key, value ) {

          if(key !== 'error') {
            $('#success').append('<p>'+value+'</p>');           

          }  
        }); 

        if( ! data.error) {     
        $('#hide').hide();              
         setTimeout(function () {
         $('input[type=submit]').attr('disabled', false);        
           window.location.href = "../index.php"; 
           //window.location.href = "../index.php?redcdid=<?php echo $cdid; ?>"; 
           // need something like above
    },     5000); 
        }

   }
  });
});
</script>

PHP 代码:

<?php
ob_start();
@session_start();
require_once("../config.php");  

$company_name = ucfirst($_POST['company_name']);    
$family_name = ucfirst($_POST['family_name']);

$msg =  array();
$msg['error'] = false;

if(empty($company_name)){   
    $msg[] = "<font color='red'>Company name required. </font>";    
    $msg['error'] = true;
}                   
if(empty($family_name)){
    $msg[] = "<font color='red'>Family name required. </font>"; 
    $msg['error'] = true;                           
}                                   


if($msg['error'] === false){

    $query_2 = "INSERT INTO contact_details (cdid, family_name, given_name, work_phone, mobile_phone, email, email_private, user_id, created_date, cid) VALUES('', '$family_name', '$given_name', '$work_phone', '$mobile_phone', '$email', '$email_private', '$user_id', '$date', '$cid')";

    $query_2 =  mysql_query($query_2);
    $last_id =  mysql_insert_id();  

    if($query_2){
        $msg[] = '<font color="green"><strong>Successfully added a new contact</strong>. </font>';                  
        $another = "close";
        }
    else{
        $msg[] = '<font color="red">Sorry we can not add a new contact details. </font>';
        $msg[] .=  mysql_error();           
        $another = "close";
        }   
}       
echo  json_encode($msg);    
?>

更新:

我在 Php apge 中使用以下代码:

if($query_2){
$msg[] = '<font color="green"><strong>Successfully added a new contact</strong>. 
</font>';                   
$msg['last_id'] = $last_id; 
}

我正在使用以下 jquery 代码:

if( ! data.error) {     
        $('#hide').hide();              
         setTimeout(function () {
         $('input[type=submit]').attr('disabled', false);        
         var last_id = data.last_id;
           window.location.href = "../index.php?redcdid=last_id"; 
    },     5000); 
        }

Answer 1

然后在您的响应中传递一个嵌套数组:

$data['msg'] = $msg;
$data['last_insert_id'] = $last_id;

echo json_encode($data);

然后在 JS 中，你需要将它们调整为:

success: function (response) {
    //             ^ now this will hold both the messages and the last insert id
    var data = response.msg; // separate them, messages does in data
    var last_id = response.last_insert_id; // last_id has the last insert id

},