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java - 在android中上传图像到服务器

转载 作者:行者123 更新时间:2023-12-01 05:45:19 25 4
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我的应用程序正在尝试通过 PHP 服务器发送图像。问题是 PHP 程序员说它应该作为数据发送。以下是我当前使用的代码,请帮我将图像转换为数据并从服务器获取响应。

InputStream is;
private int serverResponseCode;
private String serverResponseMessage;
@Override
public void onCreate(Bundle icicle)
{
super.onCreate(icicle);
setContentView(R.layout.main);
HttpURLConnection connection = null;
DataOutputStream outputStream = null;
DataInputStream inputStream = null;

String pathToOurFile = "/sdcard/siva.PNG";
Log.e("pathToOurFile",""+pathToOurFile);

String urlServer = "XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX/upload.php";
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
Log.e("URL Server",""+urlServer);

int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1*1024*1024;
Log.e("maxBufferSize",""+maxBufferSize);

try
{
FileInputStream fileInputStream = new FileInputStream(new File(pathToOurFile) );
Log.e("FIS",""+fileInputStream);
URL url = new URL(urlServer);
connection = (HttpURLConnection) url.openConnection();

// Allow Inputs & Outputs
connection.setDoInput(true);
connection.setDoOutput(true);
connection.setUseCaches(false);

// Enable POST method
connection.setRequestMethod("POST");

connection.setRequestProperty("Connection", "Keep-Alive");
connection.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);

outputStream = new DataOutputStream( connection.getOutputStream() );
outputStream.writeBytes(twoHyphens + boundary + lineEnd);
outputStream.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + pathToOurFile +"\"" + lineEnd);
outputStream.writeBytes(lineEnd);

bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];

// Read file
bytesRead = fileInputStream.read(buffer, 0, bufferSize);

while (bytesRead > 0)
{
outputStream.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}

outputStream.writeBytes(lineEnd);
outputStream.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);

// Responses from the server (code and message)
Log.e("con",String.valueOf(connection.getDoOutput()));

serverResponseCode = connection.getResponseCode();
serverResponseMessage = connection.getResponseMessage();
Log.e("response",""+serverResponseCode);
Log.e("serverResponseMessage",""+serverResponseMessage);

fileInputStream.close();
outputStream.flush();
outputStream.close();
}
catch (Exception ex)
{
Log.e("Exception Handling",""+ex);
}
}

最佳答案

最后我找到了答案,我犯了一个小错误......在上面的代码中我只更改了下一行中的一个单词

outputStream.writeBytes("Content-Disposition: form-data; name=\"上传文件\";filename=\""+ pathToOurFile +"\""+ lineEnd);

在上面的行中,主要部分是单词“uploadedfile”。这个词必须由php程序员指定,否则我们发送的文件将不会被替换。

请引用here

关于java - 在android中上传图像到服务器,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/6109778/

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