python - 我有一个 python 函数可以在脚本运行后重置脚本吗？

Question

因此，当我在 IDE 中运行此命令时，终端会弹出，我输入任何内容，它都会按预期方式输出，但随后终端会关闭。是否有一个功能可以简单地使用相同的代码重置终端中的功能，以便简单地继续输入类似游戏之类的内容？

还有什么办法可以让“<0”条件正常工作吗？我需要将字符串转换回数字才能正确执行此操作。

    # Rate our Love!! 
###   Press F5
## then input a rating for our relationship so far
print "Type a rating for our relationship" 
love_rate = raw_input()
### word answers
idk = 'idk'
no = 'no' 
yes = 'yes' 
lol = 'lol'
smh = 'smh'
def love(n):
    if n < 0 : 
        print "Why would it be negative?!" 
    elif n == 'yes' : 
        print " Well if that's the case, then I think we're gonna be just fine." 
    elif n == 'no' : 
        print 'well then... this is awkward'
    elif n == 'lol' : 
        print '''THATS NOT EVEN A NUMBER







        ......sniff'''
    elif n == 'smh' :
        print "I'm kinda mad that's an answer you thought of putting here"      
    ## numbered entries 
    elif n == '0' : 
        print " *gasps profusely* YOU DON'T DESERVE THIS PROGRAM" 
    elif n == '1' :
        print "Wow that is kinda hurtful, not gonna lie" 
    elif n == '2' : 
        print "You make me smile at least once, each and every day"
    elif n == '3' : 
        print"you wouldn't believe how annoying it was to get this program to run properly!" + " Thats all i get?"
    elif n == '4' : 
        print "let's " + "shoot a little higher than that"
    elif n == '5' : 
        print "you're unforgettable, that's what you are" 
    elif n == '6' :
        print "always have, always '____' *hint* fill in the blank " 
    elif n == '7' :
        print "i could never leave you, I love you too much" 
    elif n == '8' : 
        print "an 8/10 is still only a B, maybe I'm not trying hard enough" 
    elif n == '9' : 
        print " well, I'm not perfect yet, could have seen that one coming. Guess I just have to keep trying :)" 
    elif n == '10' : 
        print " i think you're exaggerating, i really am not that good yet"     
    elif n == '11' : 
        print """I can be a little immature sometimes and i'm sorry for that, i promise I can get better though. But i need you. I need you to help me out. Can you do that?""" 
    elif n == '12' : 
        print "I don't think the scale is supposed to go this high" 
    elif n == '13' :
        print "alright now you're pushing it." 
    elif n == '14' : 
        print "alright, THE SCALE GOES UP TO AROUND 10. CEASE" 
    elif n == '15' : 
        print " go up one more number. I DARE YOU"
    elif n == '16' : 
        print " go up one more number. see what happens"
    elif n == '17' : 
        print "one more number" 
    elif n == '18' : 
        print "one more" 
    elif n == '19' : 
        print "STOP" 
    elif n == '92412' : 
        print " I think that is one fantastic answer, can't wait for our anniversary" 
    else:
        print "I still really hope that we could get married someday." 
def reset_print():
    print """ 




Wanna Try Again? :D """ 
love(love_rate)
reset_print()

Answer 1

原因n < 0不起作用是因为 raw_input返回一个字符串和 n < 0需要一个 int 才能工作，因为你无法判断一个数字是否大于一个单词来执行你想要的操作 input而不是raw_input因为input会给你一个 int 返回，然后在你的 elif 语句中你可以去掉引号，这样它们就是数字

你可能不需要那么长的解释，但无论如何

你能做的是

n = raw_input("Rate Relationship: ")

if '-' in n:
    print ("Why would it be Negative!?")