python - 我的 python 代码有什么问题？ (乘法程序)

Question

所以我尝试制作一个乘法游戏。所以它有点有效，但是当我输入正确的答案时，它会输入“错误”两次......以及如果我输入错误的答案。

import sys #imports sys
random1=['1','2','3','4','5','6','7','8','9','10','11','12'] #makes a list with numbers 1-12
random2=['1','2','3','4','5','6','7','8','9','10','11','12'] #makes another list with numbers 1-12

from random import choice #gets a random number
while True: #makes the following code run in a loop
    print "To exit this game type 'exit'" #prints stuff
    theyputinstuffhere = raw_input("What is " + choice(random2) + " times " + choice(random1) + "? ") #asks the user things like 1*5 or some other random stuff.


    if theyputinstuffhere == "exit": #if the user typed in 'exit' then exit the game
        print "Now exiting game!" #prints stuff
        sys.exit() #exits

    elif theyputinstuffhere == int(choice(random2))*int(choice(random1)): #if what i typed is right, print stuff (I think i messed up here!)
        print "Correct!" #print stuff
    else:
       print "Wrong!" #otherwise print stuff 

我不知道我做错了什么，救命!!!!!!!!!!!!快!!!!!!!!!!!!!!!!!!

Answer 1

这应该可以完美工作

import sys 
import random

while True: 
    num1 = random.randint(0,12)
    num2 = random.randint(0,12)
    print "To exit this game type 'exit'" 
    theyputinstuffhere = raw_input("What is " + str(num2) + " times " + str(num1) + "? ") 


    if theyputinstuffhere == "exit": #if the user typed in 'exit' then exit the game
        print "Now exiting game!" #prints stuff
        sys.exit() #exits

    elif int(theyputinstuffhere) == num1*num2: 
        print "Correct!" #print stuff
    else:
        print "Wrong!" 

使用random.randint而不是选择，因为这样你就不需要一个你已经接近的列表!

当您使用 if 语句时，您正在重置 num1 和 num2 现在它会重置每个循环