java - 闰年程序问题——似乎无法让它正常运行

Question

我应该设计一个程序，要求用户输入年份，然后使用 for 方法确定该年是否是闰年，但我似乎无法让它工作。我第一次遵守时它就运行了，但它没有按照我想要的方式工作。现在我做了一些更改，但它根本没有运行。我究竟做错了什么？我必须有四种方法。

显示说明

isLeap

获取年份

显示结果

import java.util.Scanner;
public class LeapYearr
{
    public static void main(String[] args)
    {


        //Create a Scanner object for keyboard input.
        Scanner keyboard = new Scanner(System.in);

      int Year;
        displayInstructions();
        Year = getYear();
        boolean leapYear;
        leapYear = isLeap (Year);


    }

    public static void displayInstructions()
    {
         System.out.println("This program allows a users to enter a year then" +
                                    " the program determines weather or not the year entered" +
                                    "is leap Year or is not. ");
    }

    public static int getYear()

    {
    Scanner keyboard = new Scanner(System.in);

       int Year;
       System.out.print("Enter a Year of your choice: ");
        System.out.println("");
        System.out.println("");
      Year = keyboard.nextInt();

          while(Year<1000||Year>9999)
          {

              System.out.println("Invalid entry. Year has to be a 4 Digit Number!!");
                   System.out.println("");
               System.out.print("Enter a Year of your choice: ");
                    System.out.println("");
           Year = keyboard.nextInt;
             }



    return Year;
    }

    public static boolean isLeap (int Year)
    {
        if (Year % 4 != 0)
        {
            return false;
        }
        else if (Year % 400 == 0)
        {
            return true;
        }
        else if (Year % 100 == 0)
        {
            return false;
        }
        else
        {
            return true;
        }
    }
    public static void displayResults( boolean leapYear, int Year)
    {
        if (isLeapYear(Year))
        {
             System.out.println(Year + "is a leap Year.");
        }
        else
        {
             System.out.println(Year + "is not a leap Year.");
        }
    }
}

Answer 1

您的代码当前无法编译。

在 getYear() 的 while 循环中修复此问题:

while(Year<1000||Year>9999)
{
    System.out.println("Invalid entry. Year has to be a 4 Digit Number!!");
    System.out.println("");
    System.out.print("Enter a Year of your choice: ");
    System.out.println("");
    Year = keyboard.nextInt(); // you were missing '()' your parenthesis!
}