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java - 如果服务器没有响应,超时不起作用

转载 作者:行者123 更新时间:2023-12-01 05:36:10 26 4
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我遇到的问题是,当服务器没有响应时,我永远不会收到 SocketTimeOutException。 30 秒后,我收到了 IOException。

当服务器没有响应时,我需要做什么才能超时?

这是我的代码,其中第一个 URL 起作用,第二个 URL 产生 IOException 而不是 SocketTimeOutException。

公共(public)类 TestConnection {

public static final int TIMEOUT_VALUE = 5000;

public static void main(String[] arg){

try {
URL testUrl = new URL("http://www.doublegames.com/images/games140/scrabble-cubes-online_140x140.jpg");
testTimeOut(testUrl);
testUrl = new URL("http://tamblang.co.cc/wp-content/uploads/2010/08/cd7ce2_command-038-conquer-4-tiberian-twilight-140x140.jpg");
testTimeOut(testUrl);

} catch (MalformedURLException e) {
e.printStackTrace(); //To change body of catch statement use File | Settings | File Templates.
}
}
private static void testTimeOut(URL testUrl) {
try {
long start = System.nanoTime();
HttpURLConnection testConnection = (HttpURLConnection) testUrl.openConnection();
testConnection.setConnectTimeout(TIMEOUT_VALUE);
testConnection.setReadTimeout(TIMEOUT_VALUE);


BufferedReader in = new BufferedReader(new InputStreamReader(testConnection.getInputStream()));
long elapsed = System.nanoTime() - start;
System.out.println("Elapsed (ms): " + elapsed / 1000000);
System.out.println("Connection worked for " + testUrl);
} catch (SocketTimeoutException e) {
System.out.println("More than " + TIMEOUT_VALUE + " elapsed." + testUrl);
} catch(IOException ioe){
System.out.println("No timeout for " + testUrl);
}
}

}

我也尝试过使用 apaches HttpClient 但同样的事情。

private static void testTimeOut(URL testUrl) {
long start = 0;
try {
start = System.nanoTime();

HttpParams httpParams = new BasicHttpParams();
HttpConnectionParams.setConnectionTimeout(httpParams, TIMEOUT_VALUE);
HttpConnectionParams.setSoTimeout(httpParams, TIMEOUT_VALUE);
HttpClient httpClient = new DefaultHttpClient(httpParams);

HttpGet httpget = new HttpGet(testUrl.toString());
HttpResponse response = httpClient.execute(httpget);


// Get hold of the response entity
HttpEntity entity = response.getEntity();

// If the response does not enclose an entity, there is no need
// to bother about connection release
if (entity != null) {
InputStream instream = entity.getContent();
BufferedReader in = new BufferedReader(new InputStreamReader(instream));
// do something useful with the response
long elapsed = System.nanoTime() - start;
System.out.println("Elapsed (ms): " + elapsed / 1000000);
System.out.println("Connection worked for " + testUrl);

}
}catch(Exception e){
long elapsed = System.nanoTime() - start;
System.out.println("Elapsed (ms): " + elapsed / 1000000);
System.out.println("No timeout for " + testUrl + " after " + elapsed / 100000);
}
}

最佳答案

您正在尝试通过 testUrl.openConnection() 打开连接,其中 testUrl 的类型为 URL。好吧,如果你看一下具体的javadoc ,您会注意到 URL.openConnection() 永远不会抛出 SocketTimeoutException。它只能抛出IOException

关于java - 如果服务器没有响应,超时不起作用,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/8178607/

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