java - Xuggler H264 FPS 编码问题

Question

我正在尝试使用 xuggler 将一系列图像编码为 MP4 视频。然而，试图解决时基/帧速率问题让我发疯!我似乎无法获得像样的视频编码。使用 Converter.java 示例，我有

IRational num = IRational.make(24, 1);
outStreamCoder.setFrameRate(num);
outStreamCoder.setTimeBase(IRational.make(num.getDenominator(),  num.getNumerator()));

...

long tsOffset = 0;
if (outStream.getStartTime() != Global.NO_PTS && outStream.getStartTime() > 0
            && outStream.getTimeBase() != null)
{
        IRational defTimeBase = IRational.make(1, (int) Global.DEFAULT_PTS_PER_SECOND);
        tsOffset = defTimeBase.rescale(outStream.getStartTime(), outStream.getTimeBase());
}

....

long timeStamp = (3600 * count); // experimenting
IVideoPicture outFrame = converter.toPicture(worksWithXugglerBufferedImage, timeStamp);
if (outFrame.getTimeStamp() != Global.NO_PTS)
    outFrame.setTimeStamp(outFrame.getTimeStamp() - tsOffset);

对于 30 张图像，编码时长远小于 1 秒。我预计它只会一秒钟多一点。谁能帮帮我，这让我困惑了一段时间了!

Answer 1

原来我是个白痴!我根据 H.264 编码文件的 timebase 为帧分配一个 timeStamp:(1/90,000)；我真的应该从第一帧开始分配一个以微秒为单位的时间。 (例如 (1e6/fps) 的倍数)。所以我的代码应该是:

IRational fps = IRational.make(24, 1);
outStreamCoder.setFrameRate(fps);
outStreamCoder.setTimeBase(IRational.make(fps.getDenominator(),  fps.getNumerator()));

...

long timeStamp = (1e6/fps.getNumerator() * count);