python - 用户名/密码程序的打印语句不正确

Question

def login():
    UserName = input("Please enter your username: ")
    passw = input("Please enter your password: ")
    check(UserName, passw)
    if check(UserName, passw) == True:
        print("Thank you for logging in. Please enjoy these lyrics")
    else:
        print("Sorry, either your username or password is incorrect")

def check(UserName, passw):
    pword = {}
    for line in open('unames_passwords.txt','r'):
        user, password = line.split()
        pword[user] = password
        if user == UserName and password == passw:
            return True
        else:
            return False


def main():
    login()

我当前代码遇到的问题是，仅当我输入文件中包含的名字和密码时，它才会打印 if True, print 语句，但如果我在文件中输入任何其他名称和密码同一个文件，它总是打印在 else 下发出的语句。有人知道我做错了什么吗？

Answer 1

您仅根据密码文件的第一行从check()返回。如果第一个密码不匹配，则立即返回 False。

将 return False 移出循环，以便仅在扫描整个文件时执行:

def check(UserName, passw):
    for line in open('unames_passwords.txt','r'):
        user, password = line.split()
        if user == UserName and password == passw:
            return True

    return False

我在这里删除了pword字典处理；您的代码实际上并没有使用它。

您可能希望避免每次登录时调用check()两次，并且您不必测试== True； if 语句已经为您进行了测试:

def login():
    UserName = input("Please enter your username: ")
    passw = input("Please enter your password: ")
    if check(UserName, passw):
        print("Thank you for logging in. Please enjoy these lyrics")
    else:
        print("Sorry, either your username or password is incorrect")