python - 在python中获取JSON var值

Question

在Python中，提取包含JavaScript变量定义的行并获取分配给它的值(我使用BeautifulSoup从网页中抓取JavaScript)的最简单方法是什么，该值包含在大括号内(即{， })，请记住变量本身可能包含任意几层嵌套大括号。

例如与输入

var myVar  =  { "a": "123","b":"345", "c": {"c1":20,"c2":"c123", "c3": {"c3_1": {"c3_1_1":"12"}}}, "d":21, "e":["1","2"]}

我想以字符串形式获取完整的myVar值(因为我想在之后将其转换为Pythonlist) ,

{ "a": "123","b":"345", "c": {"c1":20,"c2":"c123", "c3": {"c3_1": {"c3_1_1":"12"}}}, "d":21, "e":["1","2"]}

任何帮助都会很棒，因为我是 Python 新手。

Answer 1

使用str.index查找 json 对象开始的位置和 re.sub (从 "a": "123" 生成 a:"123" )与 str.replace (将单引号更改为双引号: ['1','2'] )修复 json:

import json
import re

var = '''var myVar  =  { a: "123",b:"345", c: {c1:20,c2:"c123", c3: {c3_1: {c3_1_1:"12"}}}, d:21, e:['1','2']}'''
v = var[var.index('{'):]
v = re.sub(r'(\w*):', r'"\1":', v)
v = v.replace('\'', '\"')

>>> v
'{ "a": "123","b":"345", "c": {"c1":20,"c2":"c123", "c3": {"c3_1": {"c3_1_1":"12"}}}, "d":21, "e":["1","2"]}'
>>> json.loads(v)
{u'a': u'123', u'c': {u'c3': {u'c3_1': {u'c3_1_1': u'12'}}, u'c2': u'c123', u'c1': 20}, u'b': u'345', u'e': [u'1', u'2'], u'd': 21}