python - Python 石头剪刀布函数帮助

Question

我刚刚开始学习Python，我正在尝试为我的作业编写一个基本的剪刀石头布程序。游戏预计持续 10 轮，同时记录玩家和计算机之间的得分。我有两个具体问题。

import random

def welcome_prompt():
    print ("ROCKER PAPER SCISSORS in PYTHON Assignment")        
    print ("Rules: Rocks beats Scissors, Scissors beats Paper, Paper beats Rock")

def get_player_move():
    print ('Round ' + str(round))        
    print ("Please play one of the following")
    get_player_move = raw_input(" 1) [R]ock, 2) [P]aper, 3) [S]cissors:")

    if get_player_move == ("R"):
        print ("You used Rock!") 
        return 1              

    elif get_player_move == ("P"):        
        print ("You used Paper!")
        return 2

    elif get_player_move == ("S"):
        print ("You used Scissors!")
        return 3

    else:
        print "Invalid input, please use capitalized initial (R,P,S)"
        return get_player_move()

def get_computer_move():
        get_computer_move = random.randint(1,3)

        if get_computer_move == 1:
            print ("Computer used Rock!")
        return 1

    elif get_computer_move == 2:
        print ("Computer used Paper!")
        return 2

    elif get_computer_move == 3:
        print ("Computer used Scissors!")
        return 3



def compare_moves(get_player_move, get_computer_move):
# Rock = 1
# Paper = 2
# Scissors = 3

    if (get_player_move ==  1 and get_computer_move == 1) or (get_player_move == 2 and get_computer_move == 2) or (get_player_move == 3 and get_computer_move == 3):
    print ("It's a tie!")
    return 0  

    elif (get_player_move == 1 and get_computer_move == 3) or (get_player_move == 2 and get_computer_move == 1) or (get_player_move == 3 and get_computer_move == 2):
    print ("You win the round!")
    return 1

    elif (get_player_move == 1 and get_computer_move == 2) or (get_player_move == 2 and get_computer_move == 3) or (get_player_move == 3 and get_computer_move == 1):
    print ("You lose the round!")
    return -1

    elif (get_player_move == 4):
    print ("You didn't put in correct input, computer gets a free win")
    return -1


# Game Program

player_score = 0
comp_score = 0
round = 0


welcome_prompt()

('Round ' + str(round))
while round< 10:
    round = round + 1
    get_player_move()
    get_computer_move()
    compare_moves(get_player_move, get_computer_move)

    if compare_moves == 1:
        player_score = player_score + 1
        print 'Player Score'+ str(player_score)
        print 'Computer Score'+ str(player_score)
    elif compare_moves == -1:
        comp_score = comp_score + 1
        print 'Player Score'+ str(player_score)
        print 'Computer Score'+ str(player_score)        

print "Game Over"

首先，我无法让compare_move函数调用get_player_move和get_computer_move的返回值。游戏可以运行，没有任何错误，但它只是完全跳过比较/得分部分。我对基础知识仍然有点不确定，所以不确定缺少什么。

其次，在 get_player_move 函数中，当我输入无效的输入(例如:blah)来测试 raw_input 时，它会给出错误。

Traceback (most recent call last):
  File "C:\Python27\Rock Paper Scissors.py", line 85, in <module>
    get_player_move()
  File "C:\Python27\Rock Paper Scissors.py", line 32, in get_player_move
    return get_player_move()
TypeError: 'str' object is not callable

那么如何创建一个函数，在输入无效输入后再次请求正确的 raw_input，而不中断 while 循环？

非常感谢您的解释，谢谢

Answer 1

你有一个局部变量get_player_move 内部函数 get_player_move() ;然后您就不能再使用函数名称(全局)。

重命名get_player_move局部变量。

所以，而不是:

get_player_move = raw_input(" 1) [R]ock, 2) [P]aper, 3) [S]cissors:")

用途:

move = raw_input(" 1) [R]ock, 2) [P]aper, 3) [S]cissors:")

也许。

但是，为了获取用户输入，最好不要依赖递归。用户可能会永远点击“C”，然后您的程序将崩溃并显示 RuntimeError: maximum recursion depth exceeded 。使用循环更容易:

while True:
    move = raw_input(" 1) [R]ock, 2) [P]aper, 3) [S]cissors:")
    if move == "R":
        print ("You used Rock!") 
        return 1              

    # etc.

    else:
        print "Invalid input, please use capitalized initial (R,P,S)"

因为当做出正确选择时从函数返回，循环也会自动退出。然而，如果你读到最后并 Invalid input打印出来，while True循环再次从顶部开始，并再次要求用户输入选择。

下一步:虽然您的函数返回一个选择(整数)，但您从不存储该返回值。您必须将其存储在调用该函数的位置:

player_move = get_player_move()
computer_move = get_computer_move()
result = compare_moves(player_move, computer_move)

if result == 1:

请注意，保存返回值的不是函数名称；而是函数名称。它是一个单独的变量。 player_move被分配无论 get_player_move()例如，返回。

然后您可以将这些返回值传递给 compare_moves() ;它还返回一个结果，这里存储在 result 中以便进一步比较。