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python - 如何在pygame中使 Sprite 在窗口边缘反弹

转载 作者:行者123 更新时间:2023-12-01 05:15:56 25 4
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到目前为止,我的程序从左到右弹跳,但现在我想要在墙壁上弹跳。我怎样才能做到这一点?

delta = 5
u = 1 # x coordinate

u += delta
if u >= 440: #480 is the window size, I have it stopping at 440
delta = -5 #Go back by 5
elif u < 0:
delta = 5 #Go up by 5

更大的代码片段,它有解决方案,但 Sprite 会离开屏幕,要运行代码,请确保您有一张名为“bird.png”的图片或更改图片:

import pygame
import random

class mySprite(pygame.sprite.Sprite):
def __init__(self):
pygame.sprite.Sprite.__init__(self)
self.image = pygame.image.load("bird.png")
self.rect = self.image.get_rect()
## slef.rect(50,50,self.image.get_width(), self.image.get_height())

def update(self,x,y):
self.rect.x = x
self.rect.y = y

class newSprite(pygame.sprite.Sprite):
def __init__(self):
pygame.sprite.Sprite.__init__(self)
self.image = pygame.image.load("ball.png")
self.rect = self.image.get_rect()

def update(self,x,y):
self.rect.x = x
self.rect.y = y

class otherSprite(pygame.sprite.Sprite):
def __init__(self):
pygame.sprite.Sprite.__init__(self)
self.image = pygame.image.load("bird.png")
self.rect = self.image.get_rect()

def update(self,x,y):
self.rect.x = x
self.rect.y = y

def main():
""" Set up the game and run the main game loop """
pygame.init() # prepare the pygame module for use
surfaceSz = 480 # Desired physical surface size, in pixels.
# Create surface of (width, height), and its window.
main_surface = pygame.display.set_mode((surfaceSz, surfaceSz))

small_rect = (300, 200, 150, 90)
some_color = (255,0,0)
main_surface.fill((0,200,255))

s = mySprite()
all_sprites = pygame.sprite.Group()

s.add(all_sprites)

delta_x = 5
delta_y = 5
u = 1 # x coord
v = 1 # y coord

clock = pygame.time.Clock()
while True:
ev = pygame.event.poll() # look for any event
if ev.type == pygame.QUIT: # window close button clicked?
break # ... leave game loop

main_surface.fill((0,200,255))

#u += delta
#if u >= 440:
# delta = -5
#elif u < 0:
# delta = 5

u += delta_x
v += delta_y
if (v >=440): #assuming your y axis is 440 pixels
delta_y = -5
elif v<=0 :
delta_y = 5

if u >= 440: #440 pixels u have
delta = -5
elif u < 0:
delta = 5 #Go up by 5


all_sprites.update(u,50)
pos =(random.randint(0, surfaceSz), random.randint(0, surfaceSz))
all_sprites.draw(main_surface)

# Now the surface is ready, tell pygame to display it!
pygame.display.flip()
clock.tick(60)

pygame.quit() # once we leave the loop, close the window.

main()

最佳答案

这是一只正在移动的鸟/球,它从墙上弹起,首先,您只需要一种类型的 Sprite 类,只需使用不同的图像创建不同的实例即可。希望对您有帮助

import sys, pygame, random

SIZE = width, height = 640, 480
SPEED = [2, 2]
black = 0, 0, 0

class mySprite(pygame.sprite.Sprite):
def __init__(self, image="ball.bmp", speed=[2,2]):

pygame.sprite.Sprite.__init__(self)
self.speed = speed
self.image = pygame.image.load(image)
self.rect = self.image.get_rect()

def update(self):
global SIZE
#i used 110 px because it's the size of the image, but it's better to use the rect property of the pygame
if (self.rect.x <0) or (self.rect.x > 640-110):
self.speed[0] *= -1
if (self.rect.y<0) or (self.rect.y > 480-110):
self.speed[1] *= -1

self.rect.x =self.rect.x + self.speed[0]
self.rect.y =self.rect.y + self.speed[1]

#OR: self.rect = self.rect.move(self.speed)

def draw(self, screen):
screen.blit(self.image, self.rect)


#
pygame.init()
screen = pygame.display.set_mode(SIZE)

iaka = mySprite()

while 1:
for event in pygame.event.get():
if event.type == pygame.QUIT: sys.exit()

screen.fill(black)
iaka.draw(screen)
iaka.update()
pygame.display.flip()

关于python - 如何在pygame中使 Sprite 在窗口边缘反弹,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/23224964/

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