python - 初学者 'Guess my number'程序。当猜到正确的数字或​​猜不出来时，while 循环不会中断

Question

所以我正在学习 python，我正在尝试编写一个简单的猜数字游戏，你只有 5 次猜测，否则游戏结束。我确实在 while 循环中遇到了麻烦，无法识别数字已被猜测或已达到猜测限制。还有更好的方法来格式化我的函数吗？感谢您的帮助，第一次使用此网站。

# Guess my number
#
# The computer picks a random number between 1 and 100
# The player tries to guess it and the computer lets
# the player know if the guess is too high, too low
# or right on the money

import random

GUESS_LIMIT = 5

# functions
def display_instruct():
    """Display game instructions."""
    print("\tWelcome to 'Guess My Number'!")
    print("\nI'm thinking of a number between 1 and 100.")
    print("Try to guess it in as few attempts as possible.")
    print("\nHARDCORE mode - You have 5 tries to guess the number!\n")


def ask_number(question, low, high, step = 1):
    """Ask for a number within a range."""
    response = None
    while response not in range(low, high, step):
        response = int(input(question))
    return response


def guessing_loop():
    the_number = random.randint(1, 100)
    guess = ask_number("\nTake a guess:", 1, 100)
    tries = 1

    while guess != the_number or tries != GUESS_LIMIT:
        if guess > the_number:
            print("Lower...")
        else:
            print("Higher...")

        guess = ask_number("Take a guess:", 1, 100)
        tries += 1

    if tries == GUESS_LIMIT:
        print("\nOh no! You have run out of tries!")
        print("Better luck next time!")
    else:
        print("\nYou guessed it! The number was", the_number)
        print("And it only took you", tries, "tries!")


def main():
    display_instruct()
    guessing_loop()


# start the program
main()
input("\n\nPress the enter key to exit")

Answer 1

只要您没有达到猜测限制，您的 while 条件就会为真。

while guess != the_number or tries != GUESS_LIMIT:

您应该使用 and 连接这些条件，而不是 or。按照您现在的方式，整个条件将为 true，因为 tries != GUESS_LIMIT 为 true，即使 guess != the_number 为 false。