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java - 如何知道从网格中单击了哪个组件?

转载 作者:行者123 更新时间:2023-12-01 05:08:47 25 4
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我使用二维数组创建了一个包含 10x10 按钮的网格。我尝试了 x.getSource().getLabel() 但编译器说它们不兼容。我也想获取被单击的特定按钮。

我想获取从我制作的网格中单击的确切按钮并获取其标签。我需要使用什么方法?

import javax.swing.JFrame; //imports JFrame library
import javax.swing.JButton; //imports JButton library
import java.awt.GridLayout; //imports GridLayout library
import javax.swing.*;
import java.awt.event.*;
import java.util.*;

public class ButtonGrid extends JFrame implements ActionListener
{
JFrame frame=new JFrame(); //creates frame
JButton[][] grid; //names the grid of buttons
public int x;
public int y;
public ButtonGrid(int width, int length)
{ //constructor
char temp;
String charput;
frame.setLayout(new GridLayout(width,length)); //set layout
grid = new JButton[width][length]; //allocate the size of grid
for(int y=0; y<length; y++)
{ //start
for(int x=0; x<width; x++)
{
temp=charRand(); //get random character
charput = ""+temp; //converts character to string
grid[x][y]=new JButton(); //creates new button
frame.add(grid[x][y]); //adds button to grid
grid[x][y].addActionListener(this);
grid[x][y].setLabel(charput); //set charput as label
}
}
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
frame.pack(); //sets appropriate size for frame
frame.setVisible(true); //makes frame visible
}
/* generates randomiz letter for the button of the grid*/
public char charRand()
{
String consonantList = new String("BCDFGHL"); //list 1
String consonantList2 = new String("MNPRSTWY"); //list 2
String consonantList3= new String("JQXZVK"); //list 3
String vowelList = new String("AEIOU"); //list of vowels
int vowelOrConsonant; //holder of random number
int chosen; //selects the chosen random letter
Random randGen = new Random(); //generates random int value
char selected; //gets the random letter chosen by variable chosen

vowelOrConsonant = randGen.nextInt(4);
if (vowelOrConsonant == 0)
{
chosen = randGen.nextInt(5); //list of vowels
selected = vowelList.charAt(chosen); //selects a char from vowels
}
else if(vowelOrConsonant == 1)
{
chosen = randGen.nextInt(7); //list 1
selected = consonantList2.charAt(chosen); //selects a char
}
else if(vowelOrConsonant == 2)
{
chosen = randGen.nextInt(8); //list 2
selected = consonantList2.charAt(chosen); //selects a char
}
else
{
chosen = randGen.nextInt(6); //list 3
selected = consonantList.charAt(chosen);
}
return selected; //returns the random letter
}

public static void main(String[] args)
{
new ButtonGrid(10,10);//makes new ButtonGrid with 2 parameters
}

public void actionPerformed(ActionEvent x)
{
/* i get wrong output on this line.
* i want to get the exact button that was clicked and get its label.
*/
if (x.getSource()==grid[x][y])
JOptionPane.showMessageDialog(null,x.getSource().getLabel);
}
}

最佳答案

getSource()返回一个 Object,因此您需要将其转换为 JButton,如下所示:

public void actionPerformed(ActionEvent x) {
JOptionPane.showMessageDialog(null, ((JButton)x.getSource()).getText());
}

另请注意,getLabel()setLabel() 已弃用,应替换为 getText()setText( )

关于java - 如何知道从网格中单击了哪个组件?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/12338591/

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