cython - 我怎样才能得到自己的地址？

Question

我怎样才能做到这一点:

cdef class Tree:
    cdef object key
    cdef Tree left
    cdef Tree right

    cdef PyObject** find(self, key):
        # get the address of self
        # return &self
        # return &(<PyObject*>self)

&self失败 Cannot take address of Python variable .

&(<PyObject*>self)失败 Taking address of non-lvalue ，我不确定 self实际上是 PyObject* .

Answer 1

<void*>self和 <PyObject*>self可以很好地获取指向 self 的指针。

from ctypes import addressof, c_int
from cpython.ref cimport PyObject
from cython.operator import address
from libc.stdio cimport printf


cdef class A:
   cdef object py
   cdef int c

   def __init__(self, py, c):
        self.py = py
        self.c = c

   cdef void* addrvoid(self):
       return <void*>self

   cdef PyObject* addr(self):
       return <PyObject*>self


cpdef run():
    cdef A a
    a = A([], 1)

    # these are all equivalent
    printf('a=%lu\n', <void*>a)
    printf('a=%lu\n', <PyObject*>a)
    printf('a=%lu\n', a.addrvoid())
    printf('a=%lu\n', a.addr())

    # type casting doesnt work with the extension's c attributes because it
    # will translate to the arrow operator, like: (void *)__pyx_v_a->b)
    # printf('%lu\n', <void*>a.c)
    # printf('%lu\n', <void*>(a.c))
    # printf('%lu\n', <PyObject*>(a.c))

    # and address() dont work with python attributes
    # printf('a.py=%lu\n', <void*>address(a.py))

    # but address works with c attributes
    printf('a.c=%lu\n', address(a.c))

    # and type casting works with python attributes
    printf('a.py=%lu\n', <void*>(a.py))

    # it works with ctypes too
    i = c_int(1)
    print('cint=' + str(id(i)))
    printf('cint=%lu\n', <void*>i)

    # but it evaluates to the address of the python object
    print('cint=' + str(addressof(i)))

运行此代码将导致如下结果:

a=140516369271496
a=140516369271496
a=140516369271496
a=140516369271496
a.c=140516369271528
a.py=140516452410632
cint=140516465032184
cint=140516465032184
cint=140516465032264