java - XSD XSOM : How to parse xs:anyAttribute using XSOM Java library?

Question

我正在尝试解析这个复杂类型，但无法使用 XSOM JAVA 获取

知道如何解析它吗？

      <xsd:sequence>

      <xsd:any namespace="##other" processContents="lax" maxOccurs="unbounded"/>

      </xsd:sequence>

      <xsd:anyAttribute namespace="##other" processContents="lax"/>

Answer 1

假设此测试 XSD:

<?xml version="1.0" encoding="utf-8" ?>
<!--XML Schema generated by QTAssistant/XML Schema Refactoring (XSR) Module (http://www.paschidev.com)-->
<xsd:schema targetNamespace="http://tempuri.org/XMLSchema.xsd" elementFormDefault="qualified" xmlns="http://tempuri.org/XMLSchema.xsd" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
    <xsd:complexType name="test">
        <xsd:sequence>
            <xsd:any namespace="##other" processContents="lax" maxOccurs="unbounded"/>
        </xsd:sequence>
        <xsd:anyAttribute namespace="##other" processContents="lax"/>
    </xsd:complexType>
</xsd:schema>

您需要此代码:

    XSOMParser parser = new XSOMParser();
    //parser.setErrorHandler(...);
    //parser.setEntityResolver(...);

    parser.parse(new File(...));

    XSSchemaSet sset = parser.getResult();
    XSComplexType xt = sset.getComplexType("http://tempuri.org/XMLSchema.xsd", "test");
    XSWildcard anyAttr = xt.getAttributeWildcard();

关键是getAttributeWildcard API。