Python如何找到两个子字符串之间的字符串列表？

Question

我正在尝试获取两个字符串之间的字符串列表

text = """
something = $/I want to get this string A:blah blah 
somethingB = ($/I want to get this string as well B:blah blah blah)
"""

#I had this working to get the first found string
def find_between( s, first, last ):
    try:
        start = s.index( first ) + len( first )
        end = s.index( last, start )
        return s[start:end]
    except ValueError:
        return ""


find_between(text, '$/', ':')
# Result: I want to get this string A # 

但我希望能够搜索字符串并获得一个列表，找到......类似的东西

['I want to get this string A', 'I want to get this string as well B']

Answer 1

为什么不使用 re模块(正则表达式)来做什么？

------------------------------------------------------------ ---------- 解决方案:1 -------------------------------------- ----------------------

演示 repl.it

代码:

import re

text = """
something = $/I want to get this string A:blah blah 
somethingB = ($/I want to get this string as well B:blah blah blah)
"""

found = re.findall(r'\$\/(.+?)\:', text)
print found

输出:

['I want to get this string A', 'I want to get this string as well B']

正则表达式解释:

r'\$\/(.+?):'

\$: This will match $(This character needs to be escaped).
\/: This will match /(This character needs to be escaped).
( : This represents the beginning of extraction.
. : This will match any character except a new line.
+ : This represents match 1 or more previous character.
? : This will do a non-greedy search.
) : This represents the end of extraction.
: : This will match :.

------------------------------------------------------------ ---------- 解决方案:2 -------------------------------------- ----------------------

演示 repl.it

代码:

import re

text = """
something = $/I want to get this string A:blah blah 
somethingB = ($/I want to get this string as well B:blah blah blah)
"""

def findBetween(first, second):
    first = '\\' + first[0] + '\\' + first[1]
    found = re.findall(r'' + first + '(.+?)' + second, text)
    print found

findBetween('$/', ':')

输出:

['I want to get this string A', 'I want to get this string as well B']