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java - 尝试获取可序列化对象的输入时出现 NullPointerException

转载 作者:行者123 更新时间:2023-12-01 04:59:59 25 4
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我有 3 个类:Main、ContactLibrary 和 ContactInfo。ContactLibrary 包含一个名为 myPhoneBook 的 ArrayList。ContactInfo 由一堆包含姓名、地址等的字符串组成。

例如,用户想要搜索名称或任何涉及输入的内容。输入是在 ContactLibrary 和 ContactInfo 类中完成的——这两个类都是可序列化的对象。

但是,当达到该点时,我收到 NPE 错误。

You have 3 entry(s) saved to disc.

Hello, and welcome to Team 6's contact list.
What would you like to do?
Enter the corresponding number of choice.

1: Add an entry to the contact list.
2: Print the entire contact list.
3: Search for a contact.
4: Exit the program.

Please enter a number from 1-4.
3
What would you like to search by?
Exception in thread "main" java.lang.NullPointerException
at ContactLibrary.searchByCriteria(ContactLibrary.java:62)
at Main.optionsPrompt(Main.java:62)
at Main.main(Main.java:25)
1: Last Names.
2: Emails.
3: Zip codes.

我该怎么办?

这是我的主要:http://ideone.com/uvfK4U (包含顶部评论中的其他两个类)这是一个 UML 图:/image/RG2YO.jpg

ContactLibrary 类,根据要求:

/**
* ContactLibrary, when constructed, creates an ArrayList of ContactLibrary
* references called myPhoneBook. Every index is made to fill in objects
* of ContactInfo, which contains entries and credentials.
*
* Contains methods to create a new entry, search and print by criteria, and print list.
*/
import java.util.*;

public class ContactLibrary implements java.io.Serializable {
private static final long serialVersionUID = 1L;
private ArrayList<ContactInfo> myPhoneBook;
private Scanner libraryInput = new Scanner(System.in);

/** Constructs the ArrayList that will hold references to ContactInfo. */
public ContactLibrary() {
myPhoneBook = new ArrayList<ContactInfo>();
}

/**
* Adds an entry to the ArrayList and utilizes the set methods in
* ContactInfo.
*/
public void addEntry() {
int doAgain = 1;
do {
myPhoneBook.add(new ContactInfo());
System.out.println("Would you like to enter another contact?");
System.out.println("1: Yes.");
System.out.println("2: No.");
doAgain = libraryInput.nextInt();
} while (doAgain == 1);
}

/**
* Goes through every index in myPhoneBook and runs ArrayList.get() on them.
*/
public void printList() {
for (int i = 0; i < myPhoneBook.size(); i++) {
System.out.println(myPhoneBook.get(i));
}
}

/** Counts the number of objects within myPhoneBook and returns a string. */
public String scanDisc() {
int entryCount = myPhoneBook.size();
return "You have " + entryCount + " entry(s) saved to disc.\n";
}

/**
* The prompt for having the user search the database via criteria. Asks the
* user to enter in their search criteria.
*/
public void searchByCriteria() {
String criteria;
//libraryInput = new Scanner("System.in");
int subSubMenuChoice = 0;
System.out.println("What would you like to search by?");
System.out.println("1: Last Names.");
System.out.println("2: Emails.");
System.out.println("3: Zip codes.");
subSubMenuChoice = libraryInput.nextInt();
switch (subSubMenuChoice) {
case 1:
System.out
.println("Please enter the last name you'd like to search for:");
criteria = libraryInput.next();
searchByLastName(criteria);
break;
case 2:
System.out
.println("Please enter the e-mail you'd like to search for:");
criteria = libraryInput.next();
searchByEmail(criteria);
break;
case 3:
System.out
.println("Please enter the zip code you'd like to search for:");
criteria = libraryInput.next();
searchByZip(criteria);
break;
default:
System.out.println("Exiting");
break;
}
}

/**
* Loops through every element in the array and returns a toString of that
* index for comparing with the search criteria via contains().
*/
public void searchByEmail(String criteria) {
for (int i = 0; i < myPhoneBook.size(); i++) {
if (criteria.compareTo((myPhoneBook.get(i)).getEmail()) == 0) {
System.out.println(myPhoneBook.get(i));
} else {
System.out.print("");
}
}
}

/**
* Loops through every element in the array and returns a toString of that
* index for comparing with the search criteria via contains().
*/
public void searchByLastName(String criteria) {
for (int i = 0; i < myPhoneBook.size(); i++) {
if (criteria.compareTo((myPhoneBook.get(i)).getLastName()) == 0) {
System.out.println(myPhoneBook.get(i));
} else {
System.out.print("");
}
}
}

/**
* Loops through every element in the array and returns a toString of that
* index for comparing with the search criteria via contains().
*/
public void searchByZip(String criteria) {
for (int i = 0; i < myPhoneBook.size(); i++) {
if (criteria.compareTo((myPhoneBook.get(i)).getZipcode()) == 0) {
System.out.println(myPhoneBook.get(i));
} else {
System.out.print("");
}
}
}

/** Reorganizes the array in order by last name. */
public void sortData() {
Collections.sort(myPhoneBook);
}

}

最佳答案

您要在同一个 inputStream 上创建多个 Scanner 对象,最好只创建一个并将其传递给所使用的方法或该类的构造函数中的下一个类。

在同一流上使用多个扫描仪。扫描器可以(并且将会)消耗该流——这可能(将会)导致意想不到的副作用。最好不要这样做。

您可以将主类中的第 65 行替换为:

myLibrary.searchByCriteria(menuInput);

删除行:(在您的ContactLibrary类中)

private Scanner libraryInput = new Scanner(System.in);

关于java - 尝试获取可序列化对象的输入时出现 NullPointerException,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13519229/

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