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我在 SQL 中有 5 列,需要将它们转换为 Crystal 中的交叉表。
这就是我所拥有的:
Key | RELATIONSHIP | DISABLED | LIMITED | RURAL | IMMIGRANT
-----------------------------------------------------------------
1 | Other Dependent | Yes | No | No | No
2 | Victim/Survivor | No | No | No | No
3 | Victim/Survivor | Yes | No | No | No
4 | Child | No | No | No | No
5 | Victim/Survivor | No | No | No | No
6 | Victim/Survivor | No | No | No | No
7 | Child | No | No | No | No
8 | Victim/Survivor | No | Yes | Yes | Yes
9 | Child | No | Yes | Yes | Yes
10 | Child | No | Yes | Yes | Yes
| Victim/Survivor | Child | Other Dependent | Total |
--------------------------------------------------------------
| DISABLED | 1 | 0 | 1 | 2 |
--------------------------------------------------------------
| LIMITED | 1 | 2 | 0 | 3 |
--------------------------------------------------------------
| RURAL | 1 | 2 | 0 | 3 |
--------------------------------------------------------------
| IMMIGRANT | 1 | 2 | 0 | 3 |
--------------------------------------------------------------
| TOTAL | 4 | 6 | 1 | 11 |
--------------------------------------------------------------
IF {TABLE.DISABLED} = "YES" THEN "DISABLED" ELSE
IF {TABLE.LIMITED} = "YES" THEN "LIMITED" ELSE
IF {TABLE.IMMIGRANT} = "YES" THEN "IMMIGRANT" ELSE
IF {TABLE.RURAL} = "YES" THEN "RURAL"
IF {TABLE.DISABLED} = "YES" AND {TABLE.RELATIONSHIP} = "Victim/Survivor" THEN {TABLE.KEY} ELSE {@NULL}
(the @null formula is because Crystal, notoriously, gets confused with nulls.)
最佳答案
如果您将那些“演示”列反透视为行,它将使交叉表变得非常简单......
select
u.[Key],
u.[RELATIONSHIP],
u.[DEMO]
from
Table1
unpivot (
[b] for [DEMO] in ([DISABLED], [LIMITED], [RURAL], [IMMIGRANT])
) u
where
u.[b] = 'Yes'
select [Key], [REALTIONSHIP], [DEMO] = cast('DISABLED' as varchar(20))
from Table1
where [DISABLED] = 'Yes'
union
select [Key], [REALTIONSHIP], [DEMO] = cast('LIMITED' as varchar(20))
from Table1
where [LIMITED] = 'Yes'
union
select [Key], [REALTIONSHIP], [DEMO] = cast('RURAL' as varchar(20))
from Table1
where [RURAL] = 'Yes'
union
select [Key], [REALTIONSHIP], [DEMO] = cast('IMMIGRANT' as varchar(20))
from Table1
where [IMMIGRANT] = 'Yes'
关于sql-server - 如何从多列(在 sql 中)创建交叉表(在 Crystal 中),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/36485799/
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