Python 套接字、数据和字典

Question

因此，我尝试搜索与从客户端收到的数据相匹配的字典，但它永远找不到它。

这是我的服务器端代码:

import socket

irTable = {"a1" : "lamp", "a2" : "tv", "b1" : "lamp2", "b2" : "tv2"}

HOST = socket.gethostname()
PORT = 12345
BUFFER = 1024

s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind((HOST, PORT))
s.listen(1)

conn, addr = s.accept()
print('Connection address:', addr)
while 1:
        data = str(conn.recv(BUFFER).decode())
        if not data: break
        print("received data:", data)

for i in irTable:
        if data in irTable:
                print("Found it!")
        else:
                print("Hmm... not there!")

conn.close()

和客户端:

import socket

IP = socket.gethostname()
PORT = 12345
BUFFER = 1024

MSG = "a1"

s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((IP, PORT))
s.send(MSG.encode())

s.close()

所以此时客户端只将'a1'作为数据发送到服务器，因此

if data in irTable:

应该是这个意思

if "a1" in irTable:

但它永远不会在表中找到 a1，即使知道它在那里......我得到的只是:

>>>
Connection address: ('192.168.0.2', 58271)
received data: a1
Hmm... not there!
Hmm... not there!
Hmm... not there!
Hmm... not there!

我在这里做错了什么？

谢谢

Answer 1

问题是您在找到数据后没有跳出循环而覆盖了数据。因此数据被分配给a1，再次循环并被分配给任何内容。以下服务器代码将按您的预期工作。

import socket

irTable = {"a1" : "lamp", "a2" : "tv", "b1" : "lamp2", "b2" : "tv2"}

HOST = socket.gethostname()
PORT = 12345
BUFFER = 1024

s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind((HOST, PORT))
s.listen(1)

conn, addr = s.accept()
print('Connection address:', addr)
data = None
while not data:
    data = str(conn.recv(BUFFER).decode())

for i in irTable:
        if data in irTable:
                print("Found it!")
        else:
                print("Hmm... not there!")

conn.close()

使用 while 1 的另一种方法可能是:

while 1:
    data = str(conn.recv(BUFFER).decode())
    if data:
        break