python - 我的 Python 老虎机中的循环问题和奇怪的代码

Question

我已经阅读了所有其他老虎机帖子，并且我可以理解循环理论并获得所有其他解决方案，直到代码简单而简短。
我的阵列现在太糟糕了，我真的不明白为什么我不能玩超过一次

这里是我的整个数组，其中包括我在过去 2 天提出的其他问题的帮助。

如果这段代码很糟糕，请保持真诚和粗鲁:

import random
import time

cr = 100
print('[- play simple slot machine game -]')
time.sleep(1)
print('[- with five identical n you win -]')
time.sleep(1)
print('[- start at ' + str(cr) + 'cr place your bet -]')
time.sleep(1)
slot = []
for row in range(9):
    slot.append([None] * 9)


def print_slot(slot, empty='[ ]'):
    for row in slot:
        print(' '.join(empty if element is None else '{{: ^{}}}'.format(len(empty)).format(element) for element in row))

print_slot(slot)

time.sleep(1)
print('[- play simple slot machine game -]')
time.sleep(1)
print('[- with five identical n you win -]')
time.sleep(1)


def game_start():
    cr = 100
    bet = int(input('[- digit the num of coins to bet -] \n                 '))
    if (cr > 0) and (0 < bet <= cr):
        cr = 100 - bet
        first_n = random.randint(0, 9)
        second_n = random.randint(0, 9)
        third_n = random.randint(0, 9)
        fourth_n = random.randint(0, 9)
        fifth_n = random.randint(0, 9)
        slot[4][2] = str(first_n)
        slot[4][3] = str(second_n)
        slot[4][4] = str(third_n)
        slot[4][5] = str(fourth_n)
        slot[4][6] = str(fifth_n)

        if first_n == second_n and second_n == third_n and third_n == fourth_n and fourth_n == fifth_n:
            cr += bet * 100
            time.sleep(1)
            print('[- play simple slot machine game -]')
            time.sleep(1)
            print('[- with five identical n you win -]')
            time.sleep(1)
            print_slot(slot)
            time.sleep(1)
            print('[- with five identical n you win -]')
            time.sleep(1)
            print('[- you won!!! now you have ' + str(cr) + 'cr -]')
            bet = int(input('[- digit the num of coins to bet -] \n                 '))
            return bet

        else:
            time.sleep(1)
            print('[- play simple slot machine game -]')
            time.sleep(1)
            print('[- with five identical n you win -]')
            time.sleep(1)
            print_slot(slot)
            time.sleep(1)
            print('[- with five identical n you win -]')
            time.sleep(1)
            print('[- you loose! now you have  ' + str(cr) + 'cr -]')
            bet = int(input('[- digit the num of coins to bet -] \n                 '))
            return bet

    elif cr < 0:
        time.sleep(1)
        print('[- play simple slot machine game -]')
        time.sleep(1)
        print('[- with five identical n you win -]')
        time.sleep(1)
        print_slot(slot)
        time.sleep(1)
        print('[- with five identical n you win -]')
        time.sleep(1)
        print('[- you ran out of money 2 bet :( -]')

game_start()

Answer 1

每次下注时，您都必须-=信用，只需删除elif，我删除了一些不必要的行，添加了try/except来转换为一个 int 并捕获错误的输入以及用户退出游戏的方法。您可以在您喜欢的位置添加一两次 sleep ，但它应该按照您想要的方式运行:

def game_start():
    cr = 100
    while cr > 0:
        bet = input('[- digit the num of coins to bet -] \n or enter q to quit')
        if bet == "q": # if user wants to quit they can enter q
            print("Thanks for playing, you are leaving with ${}".format(cr))
            return # leaves/ends the function
        try: # use try/except to cast to int to catch illegal input
           bet = int(bet)
        except ValueError:
            print("Invalid input")
            continue
        if bet <= cr: # make sure we have enough credit
            cr -= bet
            first_n = random.randint(0, 9)
            second_n = random.randint(0, 9)
            third_n = random.randint(0, 9)
            fourth_n = random.randint(0, 9)
            fifth_n = random.randint(0, 9)
            slot[4][2] = str(first_n)
            slot[4][3] = str(second_n)
            slot[4][4] = str(third_n)
            slot[4][5] = str(fourth_n)
            slot[4][6] = str(fifth_n)
        else: # if we get here we tried to bet too much so use continue to go back to start of loop and ask for bet again
            print("You don't have that much credit")
            continue
        # if we get here all is good 
        if len({first_n,second_n,third_n,fourth_n,fifth_n}) == 1: # sets don't have dups so if we have five that are equal we will only have one element
                cr += bet * 100
                time.sleep(1)
                print('[- play simple slot machine game -]')
                time.sleep(1)
                print('[- with five identical n you win -]')
                time.sleep(1)
                print_slot(slot)
                time.sleep(1)
                print('[- with five identical n you win -]')
                time.sleep(1)
                print('[- you won!!! now you have ' + str(cr) + 'cr -]')
        else: # if we did not have a winning spin we will get here
            print("Hard Luck, You have {} credit left".format(cr))
    # this will print if we run out of credit        
    print('[- you ran out of money 2 bet :( -]')

cr = 100 - bet 保持将 cr - 等于 100 - 当前下注，它不会通过减少下注金额来更新 cr。

在代码中包含返还赌注将导致函数在您到达该语句时结束，无论您有多少信用，您只想在剩余 0 美元时中断/返还，或者用户想要离开。