python - Django 完整性错误处理

Question

我创建了一个用户注册网站，其中包含名字、姓氏、电话号码等。我已经成功建立了与 MySQL 数据库的连接。我需要有关 django 中 IntegrityError 处理的帮助，因为我是新手。当 2 个用户输入相同的电话号码时，django 会将我带到包含大量信息的调试页面。相反，我想立即通知用户，具有相同电话号码的另一个用户已经存在。请提供有关此的任何指示。以下是我处理表单的views.py 文件:

from django.shortcuts import render
from formProcessing.forms import UserForm




def form(request):
#This is using regular Django forms
#print request.POST
#form = EmailForm(request.POST or None)

#This is using model forms
form = UserForm(request.POST or None)
if form.is_valid():
    new_instance = form.save(commit=True)

    new_instance.save()
context = {"form": form }
template = "form.html"
return render(request,template,context)

Answer 1

在您的 UserForm 中，您可以覆盖 number 属性的 clean 方法，假设您的属性名为“number”

class UserForm(ModelForm):
    #your user form attributes and stuff


    def clean_number(self, value):
        user_number = value
        number_occurrences = User.objects.filter(number=user_number).count()
        if  number_occurrences > 0:
            raise forms.ValidationError("You number is already taken by other user")

        return self.cleaned_data

查看有关 form validation 的 django 文档

如果您不想覆盖干净的方法并在您的 View 中执行它。你可以。 (不优雅)

def form(request):
    #This is using regular Django forms
    #print request.POST
    #form = EmailForm(request.POST or None)

    #This is using model forms
    number = request.POST.get('telephone')
    number_occurrences = User.objects.filter(number=user_number).count()
    if  number_occurrences > 0:
        context = {'error':'Number already exist'}
        return render(request,template,context)

    form = UserForm(request.POST or None)
    if form.is_valid():
        new_instance = form.save(commit=True)

        new_instance.save()
        context = {"form": form }
        template = "form.html"
        return render(request,template,context)