- html - 出于某种原因,IE8 对我的 Sass 文件中继承的 html5 CSS 不友好?
- JMeter 在响应断言中使用 span 标签的问题
- html - 在 :hover and :active? 上具有不同效果的 CSS 动画
- html - 相对于居中的 html 内容固定的 CSS 重复背景?
我正在尝试创建 Spring 休息服务。我的 servlet.xml 如下所示:
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:util="http://www.springframework.org/schema/util"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd">
<bean class="org.springframework.beans.factory.annotation.AutowiredAnnotationBeanPostProcessor"/>
<!-- Database Configuration -->
<import resource="classpath:DataSource.xml"/>
<import resource="classpath:Hibernate.xml"/>
<!-- Beans Declaration -->
<import resource="classpath:Employee.xml"/>
<context:component-scan base-package="com.nilenium.service.controller" />
<mvc:annotation-driven />
<bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter">
<property name="messageConverters">
<list>
<ref bean="jsonConverter"/>
<ref bean="marshallingHttpMessageConverter"/>
</list>
</property>
</bean>
<bean id="jsonConverter" class="org.springframework.http.converter.json.MappingJacksonHttpMessageConverter"></bean>
<bean id="xstreamMarshaller" class="org.springframework.oxm.xstream.XStreamMarshaller">
<property name="autodetectAnnotations" value="true"/>
<property name="annotatedClasses">
<list>
<value>com.nilenium.employee.model.Employee</value>
<value>com.nilenium.employee.model.EmployeeRecord</value>
</list>
</property>
</bean>
<bean id="marshallingHttpMessageConverter"
class="org.springframework.http.converter.xml.MarshallingHttpMessageConverter">
<property name="marshaller" ref="xstreamMarshaller"/>
<property name="unmarshaller" ref="xstreamMarshaller"/>
</bean>
<bean class="org.springframework.web.servlet.view.ContentNegotiatingViewResolver">
<property name="order" value="1" />
<property name="ignoreAcceptHeader" value="true" />
<property name="defaultContentType" value="application/json" />
<property name="mediaTypes">
<map>
<entry key="json" value="application/json" />
<entry key="xml" value="application/xml" />
</map>
</property>
<property name="defaultViews">
<list>
<!-- JSON View -->
<bean class="org.springframework.web.servlet.view.json.MappingJacksonJsonView" />
<!-- XML View -->
<bean class="org.springframework.web.servlet.view.xml.MarshallingView">
<constructor-arg>
<bean class="org.springframework.oxm.xstream.XStreamMarshaller">
<property name="autodetectAnnotations" value="true"/>
<property name="aliases">
<props>
<prop key="employee">com.nilenium.employee.model.Employee</prop>
<prop key="employee">com.nilenium.employee.model.EmployeeRecord</prop>
</props>
</property>
</bean>
</constructor-arg>
</bean>
</list>
</property>
</bean>
</beans>
我的模型类是这样的:
package com.nilenium.employee.model;
import java.io.Serializable;
import org.codehaus.jackson.annotate.JsonProperty;
import org.codehaus.jackson.map.annotate.JsonRootName;
import com.thoughtworks.xstream.annotations.XStreamAlias;
@XStreamAlias("employee")
public class Employee implements Serializable {
private static final long serialVersionUID = 1L;
private int employeeId;
private String employeeName;
public int getEmployeeId() {
return employeeId;
}
public void setEmployeeId(int employeeId) {
this.employeeId = employeeId;
}
public String getEmployeeName() {
return employeeName;
}
public void setEmployeeName(String employeeName) {
this.employeeName = employeeName;
}
public Employee(int employeeId, String employeeName)
{
this.employeeId = employeeId;
this.employeeName = employeeName;
}
public Employee() {
}
}
我的服务 Controller 类是这样的:
package com.nilenium.service.controller;
import java.util.List;
import javax.servlet.http.HttpServletResponse;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Controller;
import org.springframework.ui.ModelMap;
import org.springframework.web.bind.annotation.ExceptionHandler;
import org.springframework.web.bind.annotation.PathVariable;
import org.springframework.web.bind.annotation.RequestBody;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.bind.annotation.ResponseBody;
import com.nilenium.employee.bo.EmployeeBo;
import com.nilenium.employee.model.Employee;
import com.nilenium.employee.model.EmployeeRecord;
@Controller
@RequestMapping("/Service")
public class NileniumServiceController {
@Autowired
private EmployeeBo employeeBo;
@ExceptionHandler
public String exceptionHandler(Exception e){
return "serviceError";
}
@RequestMapping(value = "employeeId/{employeeId}", method = RequestMethod.GET, headers = "Accept=application/xml, application/json")
public Employee getEmployeeName(@PathVariable int employeeId,
HttpServletResponse resp,
ModelMap model) {
// System.out.println("Emp Name : " + employeeName);
Employee empReturned = new Employee();
empReturned.setEmployeeId(employeeId);
empReturned.setEmployeeName("Demo Name");
return empReturned;
}
@RequestMapping(value = "/employees", method = RequestMethod.GET, headers = "Accept=application/xml, application/json")
public EmployeeRecord getAllEmployeeDetails(HttpServletResponse resp,
ModelMap model) {
List<Employee> empListReturned = employeeBo.getAllEmployee();
EmployeeRecord eRecords = new EmployeeRecord();
eRecords.setEmployeeList(empListReturned);
return eRecords;
}
@RequestMapping(value = "/storeemployee",method = RequestMethod.POST, headers = {"Accept=text/xml, application/json"})
public Employee storeEmpRecord(@RequestBody Employee employee,HttpServletResponse resp,
ModelMap model)
{
System.out.println("Emp Id received : "+employee.getEmployeeId());
System.out.println("Emp Name received : "+employee.getEmployeeName());
// Employee empReturned = employeeBo.findByEmployeeId(1);
return employee;
}
}
当我尝试将 xml 发布到 storeEmpRecord
方法时,xstream marshaller 无法将 xml 请求转换为相应的对象(Employee
对象)。
我的测试客户端是这样的:
package com.nilenium.test;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.UnsupportedEncodingException;
import java.net.URISyntaxException;
import org.apache.http.HttpEntity;
import org.apache.http.HttpException;
import org.apache.http.HttpResponse;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.entity.StringEntity;
import org.apache.http.impl.client.DefaultHttpClient;
import org.springframework.aop.framework.adapter.DefaultAdvisorAdapterRegistry;
import com.nilenium.employee.model.Employee;
import com.thoughtworks.xstream.XStream;
import com.thoughtworks.xstream.io.xml.DomDriver;
public class RestPostTest {
public static void main(String[] args) {
Employee emp = new Employee();
emp.setEmployeeId(1);
emp.setEmployeeName("Nilalohita");
XStream xStream = new XStream(new DomDriver());
xStream.alias("employee", Employee.class);
System.out.println(xStream.toXML(emp));
String xmlBody = xStream.toXML(emp);
HttpClient client = new DefaultHttpClient();
String jsonDemo = "{\"employeeId\":2,\"employeeName\":\"He-Man\"}";
try {
HttpPost post = new HttpPost("http://localhost:8080/SampleMaven/Service/storeemployee");
// post.addHeader("Accept", "application/json");
// post.addHeader("Content-Type", "application/json");
post.addHeader("Accept", "application/xml");
post.addHeader("Content-Type", "application/xml");
StringEntity entity = new StringEntity(xmlBody, "UTF-8");
// entity.setContentType("application/json");
entity.setContentType("application/xml");
post.setEntity(entity);
HttpResponse response = client.execute(post);
BufferedReader rd = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));
String line = "";
while ((line = rd.readLine()) != null) {
System.out.println(line);
}
} catch (URISyntaxException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (UnsupportedEncodingException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (HttpException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
如果我做错了什么,请告诉我。同样的事情也适用于 jaxb,在 Employee 类中使用 @XMLroot
而不是 @XStreamAlias("employee")
。
我收到以下错误。完整的堆栈跟踪是这样的
Caused by:</h3><pre>javax.servlet.ServletException: Unable to locate object to be marshalled in model: {}
at org.springframework.web.servlet.view.xml.MarshallingView.renderMergedOutputModel(MarshallingView.java:100)
at org.springframework.web.servlet.view.AbstractView.render(AbstractView.java:250)
at org.springframework.web.servlet.DispatcherServlet.render(DispatcherServlet.java:1047)
at org.springframework.web.servlet.DispatcherServlet.doDispatch(DispatcherServlet.java:817)
at org.springframework.web.servlet.DispatcherServlet.doService(DispatcherServlet.java:719)
at org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:644)
at org.springframework.web.servlet.FrameworkServlet.doPost(FrameworkServlet.java:560)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:727)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:820)
at org.mortbay.jetty.servlet.ServletHolder.handle(ServletHolder.java:487)
at org.mortbay.jetty.servlet.ServletHandler.handle(ServletHandler.java:362)
at org.mortbay.jetty.security.SecurityHandler.handle(SecurityHandler.java:216)
at org.mortbay.jetty.servlet.SessionHandler.handle(SessionHandler.java:181)
at org.mortbay.jetty.handler.ContextHandler.handle(ContextHandler.java:726)
at org.mortbay.jetty.webapp.WebAppContext.handle(WebAppContext.java:405)
at org.mortbay.jetty.handler.ContextHandlerCollection.handle(ContextHandlerCollection.java:206)
at org.mortbay.jetty.handler.HandlerCollection.handle(HandlerCollection.java:114)
at org.mortbay.jetty.handler.HandlerWrapper.handle(HandlerWrapper.java:152)
at org.mortbay.jetty.Server.handle(Server.java:324)
at org.mortbay.jetty.HttpConnection.handleRequest(HttpConnection.java:505)
at org.mortbay.jetty.HttpConnection$RequestHandler.content(HttpConnection.java:843)
at org.mortbay.jetty.HttpParser.parseNext(HttpParser.java:648)
at org.mortbay.jetty.HttpParser.parseAvailable(HttpParser.java:205)
at org.mortbay.jetty.HttpConnection.handle(HttpConnection.java:380)
at org.mortbay.io.nio.SelectChannelEndPoint.run(SelectChannelEndPoint.java:395)
at org.mortbay.thread.QueuedThreadPool$PoolThread.run(QueuedThreadPool.java:488)
最佳答案
问题出在 Controller 方法中:
@RequestMapping(value = "/storeemployee",method = RequestMethod.POST, headers = {"Accept=text/xml, application/json"})
public Employee storeEmpRecord(@RequestBody Employee employee,HttpServletResponse resp,
ModelMap model)
{
System.out.println("Emp Id received : "+employee.getEmployeeId());
System.out.println("Emp Name received : "+employee.getEmployeeName());
// Employee empReturned = employeeBo.findByEmployeeId(1);
return employee;
}
Spring MVC 不会(无法)自动将对象添加到模型
。您需要将employee
对象添加到ModelMap
。然后,模型映射被传递到编码 View ,该 View 查找它可以编码的任何对象,并将它们编码以进行响应。
无法定位要在模型中编码的对象:{}
表示编码 View 收到的 ModelMap 不包含具有 XStream 注释的对象。
希望这有帮助。
关于java - Xstream 编码器无法解码 xml 帖子正文,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/16089830/
我有以下 json: {"results": [{"columns":["room_id","player_name","player_ip"], "types":["integer","text
我在 go 中获取格式不一致的 JSON 文件。例如,我可以有以下内容: {"email": "\"blah.blah@blah.com\""} {"email": "robert@gmail.com
JavaScript中有JSON编码/解码base64编码/解码函数吗? 最佳答案 是的,btoa() 和 atob() 在某些浏览器中可以工作: var enc = btoa("this is so
我在其中一个项目中使用了 Encog,但在解码 One-Of Class 时卡住了。该字段的规范化操作之一是 NormalizationAction.OneOf,它具有三个输出。当我评估时,我想解码预
在我的 previous question关于使用 serialize() 创建对象的 CSV 我从 jmoy 那里得到了一个很好的答案,他推荐了我的序列化文本的 base64 编码。这正是我要找的。
有些事情让我感到困惑 - 为什么 this image在每个浏览器中显示不同? IE9(和 Windows 照片查看器)中的图像: Firefox(和 Photoshop)中的图像: Chrome(和
是否可以在不知道它的类型( JAXBContext.newInstance(clazz) )的情况下解码一个类,或者什么是测试即将到来的正确方法? 我确实收到了从纯文本中解码的消息 - 字符串 传入的
我正在尝试使用 openSSL 库进行 Base64 解码,然后使用 CMS 来验证签名。 下面的代码总是将缓冲区打印为 NULL。 char signed_data[] = "MIIO"; int
我有一个带有 SEL 类型实例变量的类,它是对选择器的引用。在encodeWithCoder/initWithCoder中,如何编码/解码这种类型的变量? 最佳答案 您可以使用 NSStringFro
var url = 'http://www.googleapis.com/customsearch/v1?q=foo&searchType=image'; window.fetch(url) .t
我想知道Android 2.2、2.3和3,4支持的音频/视频格式列表。我也想知道哪些Android版本支持视频编码和解码。我经历了this link,但是关于编码和解码我并不清楚。 任何人的回答都是
我在其中一个项目中使用 Encog,但在解码 One-Of 类时遇到了困难。该字段的规范化操作之一是 NormalizationAction.OneOf,它具有三个输出。当我评估时,我想解码预测值。如
我正在尝试解码现有的 xml 文件,以便我可以正确处理数据,但 XML 结构看起来很奇怪。下面是 xml 示例以及我创建的对象。 11 266 AA1001 1
对 unicode 字符进行 URL 编码的常用方法是将其拆分为 2 %HH 代码。 (\u4161 => %41%61) 但是,unicode在解码时是如何区分的呢?您如何知道 %41%61 是 \
我正在尝试将 json 字符串解码为 Map。 我知道有很多这样的问题,但我需要非常具体的格式。例如,我有 json 字符串: { "map": { "a": "b",
我有一个查询,我认为需要像这样(解码会更大) SELECT firstName, lastName, decode(mathMrk, 80, 'A', mathMrk) as decodeMat
我知道PHP函数encode()和decode(),它们对我来说工作得很好,但我想在url中传递编码字符串,但encode确实返回特殊字符,如“=”、“”' “等等...... 这显然会破坏我的脚本,
我必须解码 Basic bW9uTG9naW46bW9uTW90RGVQYXNz 形式的 http 请求的授权 header 当我解码它时online ,我得到了正确的结果 monLogin:monM
这个问题已经有答案了: Decode Base64 data in Java (21 个回答) 已关闭 8 年前。 我想知道使用哪个库进行 Base64 编码/解码?我需要此功能足够稳定以供生产使用。
我正在尝试从 Arduino BT 解码 []byte,我的连接完美,问题是当我尝试解码数组时。我得到的只是这个字符�(发送的字节数相同)我认为问题出在解码上。我尝试使用 ASCII 字符集,但仍然存
我是一名优秀的程序员,十分优秀!