java - 从 @ResponseBody 创建 JsonObject 而不使用 gson 库

Question

@ResponseBody 返回

[{"id":1010,"name":"projectname2"}] 类型 json 字符串

但是我需要一个以下的 json 字符串

[{"id":1010,"name":"projectname2","age":"21"}]

那么如何将年龄属性连接到默认生成的 json 字符串？

我使用 java spring-mvc 框架和 spring-json jar

@RequestMapping(value = "/projectsByEmployeeId/list", method = RequestMethod.GET, produces = MediaType.APPLICATION_JSON_VALUE)
@ResponseBody
public List<Project> getProjectsByEmployeeId(
        HttpServletRequest request) {
    String filter = request.getParameter("filter");
    FilterAttributes[] filterAttributes = null;
    try {
        filterAttributes = new ObjectMapper().readValue(filter,
                FilterAttributes[].class);
    } catch (Exception exception) {
        logger.error("Filtering parameter JSON string passing failed",
                exception);
    }

    if ((filterAttributes != null)
            && (!filterAttributes[0].getStringValue().isEmpty())) {
        return utilityService.getProjectsByEmployeeId(44L);//this is an example id
    } else {
        return utilityService.getProjects();
    }
}

Answer 1

实现此目的的另一种方法是纯字符串操作 -

String json = "[{\"id\":1010,\"name\":\"projectname2\"}]";
json = json.substring(0, json.length() - 2); //strip the }]

String newJSON = json.concat(",\"age\": 21}]"); // add in the new key and end

System.out.println(newJSON); // [{"id":1010,"name":"projectname2","age": 21}]