python - 查找 XPath 段落(以下兄弟？)

Question

我正在将 Selenium 与 Python 2.7.10 结合使用，并希望获取此页面上 “Description” 标题后面的段落: http://etfdb.com/etf/ROBO/

from selenium import webdriver as driver
from selenium.common.exceptions import NoSuchElementException

def scrape(driver, key):
    try:
        find_value = driver.find_element_by_xpath("//span[@class='panel__sub-heading' and . = '%s']/following-sibling::p" % key).text
    except NoSuchElementException:
        print "Not Found"
        return None
    else:
        value = re.search(r"(.+)", find_value).group().encode("utf-8")
        print value
        return value

description = scrape(driver, "Description")

我使用的 XPath 不正确，因为它没有产生任何结果。查找标题“Description”后面的段落的正确方法是什么？

Answer 1

这不是 span 标签 - 它是 h3:

//h3[@class='panel__sub-heading' and . = '%s']/following-sibling::p