python - 如何获取函数内的调用类名

Question

我有 2 个类，其方法名为 pick_up_phone。

class Work(object):

   def pick_up_phone(self):
       make_call()

class Home(object):

    def pick_up_phone(self):
       make_call()

函数make_call不是该类的一部分。如何在函数本身中打印激发该函数的类的名称，而不向该函数传递任何内容？

例如...

def make_call()
  print(????__.class__.__name__)???? <--- prints Home or Work class

Answer 1

您可以使用inspect模块:

from inspect import getouterframes, currentframe


def make_call():
    print getouterframes(currentframe())[-1][-2][0]


class Work(object):
    def pick_up_phone(self):
        make_call()


class Home(object):
    def pick_up_phone(self):
        make_call()


Home().pick_up_phone()
Work().pick_up_phone()

输出:

Home().pick_up_phone()

Work().pick_up_phone()