Django:如何获取当前 URL 标记名(用于分页)？

Question

我正在尝试使用 URL 中的 page 参数(而不是 GET 参数)进行分页。我还希望我的分页在多个不同的模板之间共享代码。

鉴于此，我想我需要做这样的事情:

网址.py:

url(r'^alias/page;(?P<page>[0-9]+)/(?P<id>.*)$', alias.get, name="alias"),

模板/别名.html:

<div>...stuff...</div>
{% include "paginator.html" %}

模板/paginator.html :

{% if page_obj.has_previous or page_obj.has_next %}
{% load filters %}
<div class="pagination clear">
    {% if page_obj.has_previous %}
        <a href="{% url somemagic %}" class="prev">&lsaquo;&lsaquo; previous</a>
...

什么是 somemagic ?

假设我想保持我的网址相同，除了设置页面 page_obj.previous_page_number

Answer 1

编辑:

您需要 somemagic是具有当前 View 名称的变量。

尝试这个:

{% with request.path_info|resolve_url_name as current_view %}
    {% url current_view page_obj.previous_page_number object.id %}
{% endwith %}

您可以使用 django-snippets 中的一些代码来实现这一点:

Variable resolving URL template tag使 {% url %} 标签从上下文解析变量。

Resolve URLs to view name函数resolve_to_name(path)返回 path 的 View 名称.您只需要创建一个使用此功能的过滤器。

此解决方案不适用于以下网址:

'alias/param1_regexp/param2_regexp/page;(?P<page>[0-9]+)/(?P<id>.*)$'

因为你对 param1 和 param2 一无所知。

可以对上面的 django-snippets 进行修改，使这种 url 工作:

第一个片段修改:

from django.template import defaulttags, VariableDoesNotExist, Variable

class ResolvingURLNode(defaulttags.URLNode):
    def render(self, context):
        original_view_name = self.view_name
        try:
            resolved = Variable(self.view_name).resolve(context)
            if len(resolved) > 1:                
                self.view_name = resolved[0]
                if resolved[1]:
                    self.args = [Variable(arg) for arg in resolved[1]]
            elif len(resolved) > 0:
                self.view_name = resolved[0]
            else:
                self.view_name = resolved

        except VariableDoesNotExist:
            pass
        ret = super(defaulttags.URLNode, self).render(context)
        # restore view_name in case this node is reused (e.g in a loop) in
        # which case the variable might resolve to something else in the next iteration)
        self.view_name = original_view_name
        return ret

defaulttags.URLNode = ResolvingURLNode

第二个片段修改

from django.core.urlresolvers import RegexURLResolver, RegexURLPattern, Resolver404, get_resolver

__all__ = ('resolve_to_name',)

def _pattern_resolve_to_name(self, path):
    match = self.regex.search(path)
    if match:
        name = ""
        if self.name:
            name = self.name
        elif hasattr(self, '_callback_str'):
            name = self._callback_str
        else:
            name = "%s.%s" % (self.callback.__module__, self.callback.func_name)
        if len(match.groups()) > 0:
            groups = match.groups()
        else:
            groups = None
        return name, groups


def _resolver_resolve_to_name(self, path):
    tried = []
    match = self.regex.search(path)
    if match:
        new_path = path[match.end():]
        for pattern in self.url_patterns:
            try:
                resolved = pattern.resolve_to_name(new_path)
                if resolved:
                    name, groups = resolved
                else:
                    name = None
            except Resolver404, e:
                tried.extend([(pattern.regex.pattern + '   ' + t) for t in e.args[0 ['tried']])
            else:
                if name:
                    return name, groups
                tried.append(pattern.regex.pattern)
        raise Resolver404, {'tried': tried, 'path': new_path}


# here goes monkeypatching
RegexURLPattern.resolve_to_name = _pattern_resolve_to_name
RegexURLResolver.resolve_to_name = _resolver_resolve_to_name


def resolve_to_name(path, urlconf=None):
    return get_resolver(urlconf).resolve_to_name(path)

基本上，resolve_to_name 返回 View 的名称及其参数作为元组，以及新的 {% url myvar %}接受这个元组并使用它来反转带有 View 名称及其参数的路径。

如果您不喜欢过滤器方法，也可以使用自定义中间件来完成。

上一个答案

您应该检查 django-pagination，这是一个非常好的 django 应用程序，易于使用并且可以完成工作。

使用 Django 分页，对可迭代对象进行分页的代码将是:
{% load pagination_tags %} {% autopaginate myiterable 10 %} <!-- 10 elements per page --> {% for item in myiterable %} RENDERING CONTENT {% endfor %} {% paginate %} <!-- this renders the links to navigate through the pages -->
myiterable 可以是任何可迭代的:列表、元组、查询集等

googlecode 的项目页面:
http://code.google.com/p/django-pagination/