python - 在 Python 中显示没有相邻重复项的文件

Question

我正在尝试编写一个显示文本文件的文件，因此我希望程序在删除任何相邻的相同行的同时显示该文件。我的问题是代码不起作用，因为我知道我遗漏了一些东西，并且我想知道如何为我面临的这个问题编写代码行？

input

1 
1 
2 
2 
1 
3 
1 
1 
1


then the output should be:
1 
2 
1 
3 
1

我现在编写的代码是:

lines = open('list.txt', 'r').readlines()

lines_set = set(lines)

out  = open('list.txt', 'w')

for line in lines_set:
    out.write(line)

print(set(f.readlines()))

Answer 1

正如问题评论中提到的，set() 不是您想要的，因为它会删除所有重复项，而不仅仅是相邻> 重复。你需要更多类似这样的东西:

with open(r'C:\Users\Gord\Desktop\list_in.txt', 'r') as f_in:
    lines = f_in.readlines()

with open(r'C:\Users\Gord\Desktop\list_out.txt', 'w') as f_out:
    prev_line = ''
    for line in lines:
        if line != prev_line:
            f_out.write(line)
            prev_line = line

with open(r'C:\Users\Gord\Desktop\list_out.txt', 'r') as f:
    for line in f.readlines():
        print(line),