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java - 无法将数据输入到数据输出流

转载 作者:行者123 更新时间:2023-12-01 04:17:44 25 4
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我正在创建一个程序,该程序从文件中读取,然后将其更改为项目的数组列表并将其发送到客户端。客户通过 ID 选择商品并输入所需金额。然后它会在服务器中更新。服务器运行多线程。当另一个客户端调用服务器时,更新的金额将提供给客户端。

我的客户端代码有问题。发生的情况是我无法输入 id 和 amt,因为程序在我输入值之前关闭。

public class ListClient {

public static void main(String[] args) throws ClassNotFoundException, IOException {

ObjectOutputStream oos = null;
ObjectInputStream ois = null;
try {
int id = 0;
int amt = 0;
Socket s1 = new Socket("localhost", 2001);
ois = new ObjectInputStream((s1.getInputStream()));

System.out.println("Connected to test server");
ListFacade2 lf = new ListFacade2();

List<Item> lm = (ArrayList<Item>) ois.readObject();
lf.setItemList(lm);
Item it = lf.pickItem();
System.out.println("Item " + it.getId() + " Amount " + it.getQty_left());
if(it.getQty_left()>0){
try (DataOutputStream dos = new DataOutputStream(s1.getOutputStream())) {
System.out.println("Enter the item id that you want:\n");
dos.writeInt(id);
System.out.println("Enter the amount of item that you want:\n");
dos.writeInt(amt);
dos.flush();
}}
else
System.out.println("Item out of stock");
} finally {
try {
if (ois != null) {
ois.close();
}
if (oos != null) {
oos.close();
}
} catch (IOException ex) {
}
}
} // end main
}

这是服务器端的代码

public class ListServer {

public static void main(String[] args) {

try {
ServerSocket sSoc1 = new ServerSocket(2001);
while (true) {
Socket inSoc1 = sSoc1.accept();
ListThread lt = new ListThread(inSoc1);
lt.start();
}
} catch (Exception e) {
System.out.println("Oh Dear! " + e.toString());
}
}
}

class ListThread extends Thread {

Socket threadSoc1;
ListFacade lf = new ListFacade();

ListThread(Socket inSoc1) throws IOException, ClassNotFoundException {
threadSoc1 = inSoc1;
lf.readItemList();
}

@Override
public void run() {
try {

ObjectOutputStream oos = new ObjectOutputStream((threadSoc1.getOutputStream()));
System.out.println("server Soc1ket runs");

oos.writeObject(lf.getListItem());
DataInputStream dis = new DataInputStream(threadSoc1.getInputStream());
int id = dis.readInt();
int amt = dis.readInt();
lf.updateItem(id, amt);
lf.displayItem();

} catch (Exception e) {
System.out.println("Whoops! " + e.toString());
}

try {
threadSoc1.close();
} catch (Exception e) {
System.out.println("Oh no! " + e.toString());
}
}
}

是因为 pickItem() 返回 null 吗?

public Item pickItem() throws IOException, ClassNotFoundException {
displayItem();
System.out.print("Please Key in item id number from above list: ");
BufferedReader b = new BufferedReader(new InputStreamReader(System.in));
Integer itno = Integer.parseInt(b.readLine());
for(int i = 0; i < im.size();i++){
if(im.get(i).id.equals(itno))

return im.get(i);

else
System.out.println("No such item");
}
return null;
}

最佳答案

请参阅此处的第一个示例:Scanner

如果您想询问用户输入,您必须从 System.in 中读取(使用扫描仪或类似工具来完成)。

像这样...

Scanner fromUser = new Scanner(System.in);
try (DataOutputStream dos = new DataOutputStream(s1.getOutputStream())) {
System.out.println("Enter the item id that you want:\n");
id = fromUser.nextInt();
dos.writeInt(id);
System.out.println("Enter the amount of item that you want:\n");
amt = fromUser.nextInt();
dos.writeInt(amt);
dos.flush();
}

当然,实现同一目标的方法还有很多。这只是一个...

关于java - 无法将数据输入到数据输出流,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19268635/

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