python - Wunderground api 搜索栏

Question

我目前正在编写一个搜索天气的程序。我正在尝试创建一个选项，您可以在其中搜索您的位置，但它似乎不起作用。

  from urllib.request import Request, urlopen
  import json
  import re
  location = input('location you would like to know the weather for')

API_KEY = '<API-KEY>'
url = 'http://python-weather-api.googlecode.com/svn/trunk/ python-weather-api' + API_KEY +'/geolookup/conditions/q/IA/'+ location +'.json'


response = urllib.request.Request(url)


def response as request(url)
json_string = response.read().decode('utf8')
parsed_json = json.loads(json_string)
location = parsed_json['location']['city']


temp_f = parsed_json['current_observation']['temp_f']
print("Current temperature in %s is: %s" % (location, temp_f))
response.close()

我不断收到此错误

Answer 1

还不能发表评论(因为我刚刚加入 SO，声誉太低)，但是关于您的“urllib 未定义”问题，这与您如何导入 urlopen 函数有关。

而不是:

urllib.urlopen(url)

尝试:

urlopen(url)

编辑:这是您的代码，已修复:

from urllib.request import urlopen
import json

location = input('location you would like to know the weather for')

API_KEY = '<API-KEY>'
url = 'http://api.wunderground.com/api/' + API_KEY + '/geolookup/conditions/q/IA/'+ str(location) +'.json'

response = urlopen(url)

json_string = response.read().decode('utf8')
parsed_json = json.loads(json_string)
location = parsed_json['location']['city']
temp_f = parsed_json['current_observation']['temp_f']
print("Current temperature in %s is: %s" % (location, temp_f))

适用于多摩和爱荷华州的其他城市。但请注意，像 Des Moines 这样的地名不起作用，因为 URL 中不允许有空格 - 您必须注意这一点。 (API 的示例建议用 _ 表示空格 http://www.wunderground.com/weather/api/d/docs?MR=1 )。祝你好运!