php json_decode 和 Jquery Nestable

Question

我正在使用 jquery Nestable (http://dbushell.github.io/Nestable/)。

当我更改可嵌套元素的顺序时，我试图从中拦截数据..

$('.dd').nestable().on('change', function() {
  var json_text = $('.dd').nestable('serialize');
  $.post("/includes/processes/core.php", {
    cmd: 'nestable',
    table: table,
    data: json_text
  }, function(response){
    alert(response);
  });
});

在 core.php 中我已经完成:

$data = $_POST['data'];
$data = json_decode($data, true);
function parseJsonArray($jsonArray, $parentID = 0) {
  $return = array();
  foreach ($jsonArray as $subArray) {
    $returnSubSubArray = array();
    if (isset($subArray['children'])) {
  $returnSubSubArray = parseJsonArray($subArray['children'], $subArray['id']);
    }
    $return[] = array('id' => $subArray['id'], 'parentID' => $parentID);
    $return = array_merge($return, $returnSubSubArray);
  }
  return $return;
}

$readbleArray = parseJsonArray($data);

我必须操作这个数组，但我无法继续，因为响应是:

"json_decode() expects parameter 1 to be string, array given in core.php on line (where is "$data = json_decode($data, true;")"

如果我用 json_encode($data) 更改 json_decode($data, true) ，这就是响应:

"Invalid argument supplied for foreach() in core.php on line (where is "foreach ($jsonArray as $subArray);")"

请帮助我..

Answer 1

尝试删除此行，因为 $.post 不执行 json 编码。

$data = json_decode($data, true);