python - 编写验证码装饰器时出现属性错误

Question

我写了一个验证码装饰器...

def validate_captcha(view):
    '''Decorator to validate a captcha based on settings'''

    def failure():
        return HttpResponse('There was an error, please refresh and try again')

    def wrap(request, *args, **kwargs):
        if request.method == 'POST':

            url = "https://www.google.com/recaptcha/api/siteverify"
            values = {
                'secret': settings.GOOGLE_RECAPTCHA_SECRET_KEY,
                'response': request.POST.get(u'g-recaptcha-response', None),
                'remoteip': request.META.get("REMOTE_ADDR", None),
            }

            data = urllib.urlencode(values)
            req = urllib2.Request(url, data)
            response = urllib2.urlopen(req)
            result = json.loads(response.read())

            # result["success"] will be True on a success
            if result["success"]:
                return view
            else:
                return failure
        return failure
    return wrap

然后在 View 上使用它...

@validate_captcha
def sendemail(request):
    ...

但随后我收到属性错误...

Traceback:
File "/home/jeff/Django/langalang/venv/local/lib/python2.7/site-packages/django/core/handlers/base.py" in get_response
  223.                 response = middleware_method(request, response)
File "/home/jeff/Django/langalang/venv/local/lib/python2.7/site-packages/django/middleware/common.py" in process_response
  138.         if response.status_code == 404 and not settings.DEBUG:

Exception Type: AttributeError at /ko/contact/sendemail
Exception Value: 'function' object has no attribute 'status_code'

我认为...发生这种情况是因为它返回了一个函数，但我无法弄清楚为什么 django 将其视为响应，因为响应已经在我的装饰器中处理，并且我验证了它是否已到达返回点'结果[“成功”]'

Answer 1

我认为您应该调用 failure() 函数，以便您实际上拥有从包装装饰器返回的 HttpResponse 。替换:

return failure

与:

return failure()

并且， View 也是如此，调用它:

return view(request, *args, **kwargs)