python - ZeroDivisionError : float division by zero, 如何在用户首次输入特定字符串时打印某些内容然后退出？

Question

我正在做一项作业，要求我编写一个计算列表平方平均值的程序。

因此，如果程序正常，它将显示:

avgSumOfSquares()
Enter next number: 3.27
Enter next number: -1.9
Enter next number: 6
Enter next number: -1
Enter next number: end
The average of the sum of the squares is: 12.825725
12.825725
avgSumOfSquares()
Enter next number: end
No numbers were entered.

但是，当我输入 end 时，我的程序告诉我 Traceback(最近一次调用最后一次):

File "<pyshell#9>", line 1, in <module> 
   avgSumOfSquares()  
File , line 34, in avgSumOfSquares  
   average = num_sum / amount  
ZeroDivisionError: float division by zero  

这是我的代码

def avgSumOfSquares():
    input_list = []
    user_input = 0
    num_sum = 0             

    while user_input != "end":

        input_list.append(float(user_input))
        user_input = input("Enter next number :")

        squared = [i ** 2 for i in input_list]

        num_sum = sum(squared)
        amount = len(squared) - 1

        if len(input_list) == 0:
            print("No numbers were entered.")                     

        average = num_sum / amount

        print("The average of the sum of the squares is: ", average)

Answer 1

它失败了，因为对于第二个数字，input_list 的长度为 1。因此，ammount 将为 0。您应该将平均检查器放在elif block 如下:

while user_input != "end":
    input_list.append(float(user_input))
    user_input = input("Enter next number :")

    if len(input_list) == 0:
        print("No numbers were entered.")
    elif len(input_list) > 1:
        squared = [i ** 2 for i in input_list]

        num_sum = sum(squared)
        amount = len(squared) - 1
        average = num_sum / amount

        print("The average of the sum of the squares is: ", average)

这应该可以解决您的问题，但我不知道为什么您将 ammount 定义为 len(squared) - 1。 3 个数字的平均值是 3 个数字的总和除以 3，而不是 2。如果您正确计算平均值，elif 可能是 else 相反。