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python - 如何在 turtle 圆圈和矩形内生成随机点?

转载 作者:行者123 更新时间:2023-12-01 04:05:47 24 4
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在 turtle 图形内,我画了一个矩形和一个圆形。如何在每个形状中放置 10 个随机点?这是我的代码:

import turtle
import math
import random

# draw a rectangle at a specific location
def drawRectangle(x = -75, y = 0, width = 100, height = 100):
turtle.penup() # Pull the pen up
turtle.goto(x + width / 2, y + height / 2)
turtle.pendown() # Pull the pen down
turtle.right(90)
turtle.forward(height)
turtle.right(90)
turtle.forward(width)
turtle.right(90)
turtle.forward(height)
turtle.right(90)
turtle.forward(width)


# Draw a circle at a specific location
def drawCircle(x = 50, y = 0, radius = 50):
turtle.penup() # Pull the pen up
turtle.goto(x, -50)
turtle.pendown() # Pull the pen down
turtle.begin_fill() # Begin to fill color in a shape
turtle.circle(radius)

最佳答案

在矩形内生成随机点非常简单。您只需生成一个随机 x 坐标,范围从原点位置(在您的情况下为 -75)到其末尾,即原点 + 宽度(-75 + 100)。然后,您将对 y 坐标执行相同的操作。然后,移动到生成的位置并绘制一个点。

我的代码:

# draw random dots inside of rectangle
# @param origin: is a touple, containing `x` and `y` coordinates
# @param number_of_dots: int, number of dots
# @param size: is a touple, containing `width` and `height` of rectangle
def draw_random_dots_in_rectangle(origin, number_of_dots, size=RECTANGLE_SIZE):
# loops number_of_dots times
for _ in range(number_of_dots):
# generate a random position inside of given rectangle
# using min/max, because of possible negative coordinates
# weakness - does also place dots on the edges of the rectangle
rand_x = randint(min(origin[0], origin[0] + size[0]), max(origin[0], origin[0] + size[0]))
rand_y = randint(min(origin[1], origin[1] + size[1]), max(origin[1], origin[1] + size[1]))
# moves to the random position
move_turtle_to((rand_x, rand_y))
# creates a dot
t.dot(DOT_DIAMETER)

但是,用圆做同样的事情是不可能的。它要复杂得多,需要了解 analytic geometry 。对于您的情况,您需要 equation of circles 。这样您就可以计算生成的位置是否在给定圆内。

我的代码:

# draw random dot inside of circle
# @param origin: is a touple, containing `x` and `y` coordinates
# @param number_of_dots: int, number of dots
# @param radious: int, radious of circle
def draw_random_dots_in_circle(origin, number_of_dots, radius=CIRCLE_RADIOUS):
# loops number_of_dots times
for _ in range(number_of_dots):
# loops until finds position inside of the circle
while True:
# generates random x position
# subtracting radious and adding double of radious to simulate bounds of square
# which would be large enought to fit the circle
rand_x = randint(min(origin[0] - radius, origin[0] + radius * 2),
max(origin[0] - radius, origin[0] + radius * 2))
# generated random y position
# adding double of radious to sumulate bounds of square
# which would be large enought to fit the circle
rand_y = randint(min(origin[1], origin[1] + radius * 2),
max(origin[1], origin[1] + radius * 2))

# test if the generated position is in the radious
if (origin[0] - rand_x) ** 2 + (origin[1] + radius - rand_y) ** 2 < radius ** 2:
# if it is, move to the position
move_turtle_to((rand_x, rand_y))
# draw dot
t.dot(DOT_DIAMETER)
# break out from the infinite loops
break

本质上,它与以前的过程相同,但进行了等式检查。
我希望这至少有一点帮助。我自己曾多次努力弄清楚如何在计算机科学中做某些事情,并且很多次我发现解析几何就是答案。所以我强烈建议至少检查一下。
我的洞代码:

#!/usr/bin/env python3

import turtle
from random import randint

RECTANGLE_SIZE = 60, 80
CIRCLE_RADIOUS = 10
DOT_DIAMETER = 3

t = turtle.Turtle() # turtle object
t.speed(0) # set the fastest drawing speed

# move turtle to position without drawing
# @param: position is a touple containing `x` and `y` coordinates
def move_turtle_to(position):
t.up() # equivalent to .penuo()
t.goto(position[0], position[1])
t.down() # equivalent to .pendown()


# draws a rectangle from given origin with given size
# @param origin: is a touple, containing `x` and `y` coordinates
# @param size: is a touple, containing `width` and `height` of rectangle
def draw_rectangle(origin, size=RECTANGLE_SIZE):
# movese to the origin
move_turtle_to(origin)

# simple way of drawing a rectangle
for i in range(4):
t.fd(size[i % 2])
t.left(90)

# draws a circle from given origin with given radious
# @param origin: is a touple, containing `x` and `y` coordinates
# @param radious: int, radious of circle
def draw_circle(origin, radius=CIRCLE_RADIOUS):
# moves to the origin
move_turtle_to(origin)
# draws the circle
t.circle(radius)


# Now to what you asked
# draw random dots inside of rectangle
# @param origin: is a touple, containing `x` and `y` coordinates
# @param number_of_dots: int, number of dots
# @param size: is a touple, containing `width` and `height` of rectangle
def draw_random_dots_in_rectangle(origin, number_of_dots, size=RECTANGLE_SIZE):
# loops number_of_dots times
for _ in range(number_of_dots):
# generate a random position inside of given rectangle
# using min/max, because of possible negative coordinates
# weakness - does also place dots on the edges of the rectangle
rand_x = randint(min(origin[0], origin[0] + size[0]), max(origin[0], origin[0] + size[0]))
rand_y = randint(min(origin[1], origin[1] + size[1]), max(origin[1], origin[1] + size[1]))
# moves to the random position
move_turtle_to((rand_x, rand_y))
# creates a dot
t.dot(DOT_DIAMETER)

# draw random dot inside of circle
# @param origin: is a touple, containing `x` and `y` coordinates
# @param number_of_dots: int, number of dots
# @param radious: int, radious of circle
def draw_random_dots_in_circle(origin, number_of_dots, radius=CIRCLE_RADIOUS):
# loops number_of_dots times
for _ in range(number_of_dots):
# loops until finds position inside of the circle
while True:
# generates random x position
# subtracting radious and adding double of radious to simulate bounds of square
# which would be large enought to fit the circle
rand_x = randint(min(origin[0] - radius, origin[0] + radius * 2),
max(origin[0] - radius, origin[0] + radius * 2))
# generated random y position
# adding double of radious to sumulate bounds of square
# which would be large enought to fit the circle
rand_y = randint(min(origin[1], origin[1] + radius * 2),
max(origin[1], origin[1] + radius * 2))

# test if the generated position is in the radious
if (origin[0] - rand_x) ** 2 + (origin[1] + radius - rand_y) ** 2 < radius ** 2:
# if it is, move to the position
move_turtle_to((rand_x, rand_y))
# draw dot
t.dot(DOT_DIAMETER)
# break out from the infinite loops
break


# example code
draw_rectangle((0, 0))

draw_random_dots_in_rectangle((0, 0), 50)

draw_circle((-20, -20))

draw_random_dots_in_circle((-20, -20), 20)

input()

关于python - 如何在 turtle 圆圈和矩形内生成随机点?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/35612938/

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