javascript - 在 JavaScript 函数上获取周五停止的日期

Question

如何让我的代码只显示周五之前的日期，它目前显示周六之前的日期:

var dayString = ["Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"];

var now = new Date();
var currentDay = now.getDay(); // return 0 for Sunday, 6 for Saturday
var result = [];
var tempDate = new Date(now.getTime());
tempDate.setDate(now.getDate() - (currentDay + 6) % 7); // now tempDate is previous Monday
while (tempDate.getDay() != 0) {
  var currentMonth = tempDate.getMonth() + 1;
  if (currentMonth < 10) currentMonth = "0" + currentMonth;
  result.push([tempDate.getDay() - 1, tempDate.getDate() + "-" + currentMonth + "-" + tempDate.getFullYear(), dayString[tempDate.getDay()]]);
  tempDate.setDate(tempDate.getDate() + 1);
}
console.log(result);

https://jsfiddle.net/xut9tkpz/

Answer 1

如果您想获取下周五之前的日期，请使用以下命令:

var now = new Date();
var results = [];
while(now.getDay() !== 5) {
 results.push(new Date(now)); // push Date Object to results;
 now.setDate(now.getDate() + 1);
}

如果您想获取上周五之前的日期:

var now = new Date();
var results = [];
while(now.getDay() !== 5) {
 results.push(new Date(now)); // push Date Object to results;
 now.setDate(now.getDate() - 1);
}

如果您想获取过去 1 周内直到上周五的日期:

var now = new Date();
now.setDate(now.getDate() - 7);
var results = [];
while(now.getDay() !== 5) {
 results.push(new Date(now)); // push Date Object to results;
 now.setDate(now.getDate() + 1);
}

如果您想将星期五包含在结果对象中，只需将 5 更改为 6