python - 如何在pyQt5中接收ActiveX事件？

Question

我一直在使用pyQt4。我想转换 pyQt5.但是，我无法使用old-style signal and slot在 pyQt5 中，因为 pyQt5 仅支持 new-style signal and slot 。因此，我无法接收来自 ActiveX 的事件。

请给我解决方案。

此代码是pyQt4版本。

from PyQt4.QtCore import SIGNAL, QObject
from PyQt4.QAxContainer import QAxWidget

class ActiveXExtend(QObject):
    def __init__(self, view):
        super().__init__()
        self.view = view
        self.ocx = QAxWidget("KHOPENAPI.KHOpenAPICtrl.1")

        # receive ActiveX event.
        self.ocx.connect(self.ocx, SIGNAL("OnReceiveMsg(QString, QString, QString, QString)"), self._OnReceiveMsg)

    # event handler
    def _OnReceiveMsg(self, scrNo, rQName, trCode, msg):
        print("receive event")

我尝试转换 pyQt5。

from PyQt5.QtCore import QObject
from PyQt5.QAxContainer import QAxWidget

class ActiveXExtend(QObject):

    def __init__(self, view):
        super().__init__()
        self.view = view
        self.ocx = QAxWidget("KHOPENAPI.KHOpenAPICtrl.1")
        # receive ActiveX event. 
        # old-style is not supported.
        # self.ocx.connect(self.ocx, SIGNAL("OnReceiveMsg(QString, QString, QString, QString)"), self._OnReceiveMsg)

    # event handler
        def _OnReceiveMsg(self, scrNo, rQName, trCode, msg):
            print("receive event") 

Answer 1

终于找到解决办法了。 pyQt5 支持来自 ActiveX 事件的信号。

如果 ActiveX 有“OnReceiveMsg”事件，QAxWidget 实例支持“OnReceiveMsg”信号。因此，我修复了这样的代码。

from PyQt5.QtCore import QObject
from PyQt5.QAxContainer import QAxWidget

class ActiveXExtend(QObject):

    def __init__(self, view):
        super().__init__()
        self.view = view
        self.ocx = QAxWidget("KHOPENAPI.KHOpenAPICtrl.1")
        # receive ActiveX event. 
        self.ocx.OnReceiveMsg[str,str,str,str].connect(self._OnReceiveMsg)

    # event handler
        def _OnReceiveMsg(self, scrNo, rQName, trCode, msg):
            print("receive event")