Python时间增量错误: skipping a day when trying to get tomorrow

Question

我有以下代码:

import time
from datetime import date, datetime, timedelta


def getNextDay(last_day):
    #Returns tomorrows timestamp at two times: 00:00 and 23:59
    last_day = datetime.utcfromtimestamp(last_day)
    tomorrow = last_day + timedelta(days=1)
    tomorrow_start = datetime(tomorrow.year, tomorrow.month, tomorrow.day, 0, 0, 0, 0)
    tomorrow_end = datetime(tomorrow.year, tomorrow.month, tomorrow.day, 23, 59, 0, 0)
    return [time.ctime(int(tomorrow_start.strftime("%s"))), time.ctime(int(tomorrow_end.strftime("%s")))]


last_day = 1370054073 #unix-timestamp

print "The day is:"
print time.ctime(last_day)

print "The next day is:"
print getNextDay(last_day)

当我运行它时，输出是:

The day is:
Fri May 31 23:34:33 2013
The next day is:
['Sun Jun  2 00:00:00 2013', 'Sun Jun  2 23:59:00 2013']

我找不到问题所在，因为 getNextDay() 函数似乎是正确的:我想从 1370054073 获取明天的 00:00 和 23:59。但它跳过一天，第二天的输出应该是 ['Sat Jun 1 00:00:00 2013', 'Sat Jun 1 23:59:00 2013']

有人可以告诉我哪里做错了吗？

Answer 1

来自 time.ctime 的文档:

Convert a time expressed in seconds since the epoch to a string representing local time. If secs is not provided or None, the current time as returned by time() is used. ctime(secs) is equivalent to asctime(localtime(secs)). Locale information is not used by ctime().

因此，当您使用 print time.ctime(last_day) 时，您会看到基于本地时间的时间:

Fri May 31 23:34:33 2013

但是，当我使用它时，我看到了不同的时间:

Sat Jun  1 08:04:33 2013

您可以通过以下方式获取实际的UTC时间:

>>> datetime.utcfromtimestamp(last_day)
datetime.datetime(2013, 6, 1, 2, 34, 33)

而且，正如您所看到的，现在已经是 6 月 1 日，因此您的函数运行正常，并且不会跳过任何天。