javascript - 组合两个输入事件

Question

我的目标是从输入中删除 javascript，所以我正在编写一些 jquery

JavaScript:

    <input type="text" id = "IDthisinput'" class="CLthisinput'"  placeholder="First"
            onChange   = "dosomething();"
            onKeyPress = "this.onchange();"
            onpaste    = "this.onchange();"
            oninput    = "this.onchange();"
    />
    <span id="ReturnedMsg"></span>
    <span id="IDActionVal"></span>

jquery:

    $('.CLthisinput').on('keyup', function () {
            $('#ReturnedMsg').html(dotuff('#'+this.id,$(this).val()));
            $('#IDActionVal').html('#'+this.id + '  ' + 'keyup ' + $(this).val());
    });
    $('.CLthisinput').on('paste', function () {
            $('#ReturnedMsg').html(dotuff('#'+this.id,$(this).val()));
            $('#IDActionVal').html('#'+this.id + '  ' + 'keyup ' + $(this).val());
    });

当涉及到将上面的内容缩短为这样的内容时，我感到很困惑:

    $('.CLthisinput').on('keyup', 'paste', function () {
            var theaction = event
            $('#ReturnedMsg').html(dotuff('#'+this.id,$(this).val()));
            $('#IDActionVal').html('#'+this.id + '  ' + theaction + '  ' + $(this).val());
    });

如何让这些事件协同工作？!

Answer 1

另一种方法也是外包该功能，如下所示:

var helper = function() {
  $('#ReturnedMsg').html(dotuff('#'+this.id,$(this).val()));
  $('#IDActionVal').html('#'+this.id + '  ' + 'keyup ' + $(this).val());
}
$('.CLthisinput').on('keyup', helper);
$('.thisinput').on('paste', helper);