python - CodeWars "Find The Parity Outlier"错误？

Question

这个问题已经有答案了:

Why does the division get rounded to an integer? [duplicate] (13 个回答)

已关闭 7 年前。

我正在完成this Codewars exercise 。以下是说明:

You are given an array (which will have a length of at least 3, but could be very large) containing integers. The integers in the array are either entirely odd or entirely even except for a single integer N. Write a method that takes the array as an argument and returns N.

For example:

[2, 4, 0, 100, 4, 11, 2602, 36]

Should return: 11

[160, 3, 1719, 19, 11, 13, -21]

Should return: 160

但是，当我提交以下代码时:

def ifeven(list):
     #Determine if we are dealing with list of evens or odds
    sum = 0
    for ran in (0,1,2):
        sum += abs(list[ran])%2
    avg = sum/3
    r_avg = round(avg)
    return r_avg == 0

def find_outlier(integers):
    even =  ifeven(integers)
    new = []
    for num in integers:
        new.append(num%2)
    if even:
        loc = new.index(1)
    else:
        loc = new.index(0)
    return integers[loc]

使用此测试用例(请参阅练习链接):

test.assert_equals(find_outlier([1,2,3]), 2)

由于某些原因，我收到错误 1 should equal 2即使我在另一个编译器上运行代码，我也会得到 2作为(正确)答案。

是我的代码有问题还是 Codewars 的编译器有问题？

Answer 1

根据/u/Prune 的建议，答案如下:

检查正在使用的Python版本。 Python 2 和 3 对/运算符的处理方式不同。参见这里:Division in Python 2.7. and 3.3