Python 乘法数组连接

Question

如果我有一个大小不一致的数组，则列表由(不一致的)数量的列表组成:

 lists = [List1, List2, List3,...ListN]

其中每个包含的列表的大小不一致。

如何以乘法方式连接每个包含的数组的内容。

目标输出示例:

A = ["A","B","C","D"]
B = ["1","2","3","4"]
C = ["D","E","F","G"]
A[0-N] + B[0-N] + C[0-N]

Giving ["A1D","B1D","C1D","D1D",
        "A2D","B2D","C2D","D2D"
        "A3D","B3D","C3D","D3D"
        "A4D","B4D","C4D","D4D"
        "A1E","B1E","C1E","D1E"

         ... "C4G","D4G"  ]

对于这个具体示例，它应该生成一个长度为 4^3 的列表。(列表长度为列表数量的幂)

但是列表长度不是恒定的，所以它实际上是

List1 长度 * List2 长度 * List3 长度 * ... * ListN 长度

对于不一致的列表长度:

  A = ["A","B"]
  B = ["1","2","3","4"]

 = ["A1","A2","A3","A4","B1","B2","B3","B4"]

我尝试过 python map 和 zips，但我在执行时遇到困难，例如:

zip(list1, list2, list3)

何时:

列表数量不一致

这些列表不是单独存储的，而是整理在一个大列表中，

且列表大小不一致

其他 SO 问题中描述的方法仅解决大小一致、2 个列表的情况。我在这种情况下应用这些技术时遇到困难。

Answer 1

import itertools
A = ["A","B"]
B = ["1","2","3","4"]
list(itertools.product(A, B))

通用

lists_var = [List1, List2, List3,...ListN]
list(itertools.product(*lists_var))