Mule Rest异常处理

Question

骡子流:

<jersey:resources doc:name="REST">
<component class="com.test.qb.rest.MapIIFContent"/>
<jersey:exception-mapper class="com.test.qb.exception.IIFExceptionMapper" />
</jersey:resources>
<catch-exception-strategy doc:name="Audit Exception" >      
    <set-variable variableName="status" value="Failure" doc:name="Status"/>
    <flow-ref name="QB:audit" doc:name="audit"/>
    <http:response-builder status="500" contentType="application/json" doc:name="Status Code"/>
</catch-exception-strategy>
<logger message=" ===Reached here====" level="INFO" doc:name="Logger"/> <!-- Line 10-->

Java Rest 组件:

休息组件:

try{
    String s =null;
    s.toString();// throw nullpointer exception
} catch (IIFException e) {
    return Response.status(500).entity(e.getMessage()).type("Application/json").build();
}
return Response.ok(res).build();

当我运行它时，它会在 Java Rest 组件中捕获错误状态为 500 的块。
但是在骡子流中我期望流应该达到

'catch-exception-strategy doc:name="Audit Exception" >

块，但它没有到达那里，而是到达第 10 行。我该如何处理？

Answer 1

我让休息组件抛出检查的自定义异常而不是返回休息响应状态:

try{
    String s =null;
    s.toString();
} catch (IIFException e) {
    throw new IIFException(e.toString(),e.getCause());
}
return Response.ok(res).build();

在我的异常流中，将其设为:

<catch-exception-strategy doc:name="Audit Exception" >
    <expression-component doc:name="Create error response"><![CDATA[#[payload = "{\"status\":\"error\", \"message\":\"" + exception.cause.message + "\"}"]]]></expression-component>
    <http:response-builder status="500" contentType="application/json" doc:name="Status Code"/>
</catch-exception-strategy>