javascript - 简单的JS函数不起作用

Question

有人知道为什么我的 JS 函数不起作用/我的价格 div 根本不显示任何内容吗？

HTML:

<div id="variant">
    <label><input type="radio" name="toggle" id="3"><span>A</span></label>
    <label><input type="radio" name="toggle" id="12" checked="checked"><span>B</span></label>
    <label><input type="radio" name="toggle" id="24"><span>C</span></label>
</div>
<br>
<div id="price"></div>

JS:

function setPrice() {
  if (document.getElementById('3').checked) {
    document.getElementById('price').innerHTML = "19,99€";
  } else if (document.getElementById('12').checked) {
    document.getElementById('price').innerHTML = "<<<";
  } else (document.getElementById('24').checked) {
    document.getElementById('price').innerHTML = "xxx";
  }
}

Answer 1

“else”条件不接受语句，而是 IF/ELSE IF 接受语句。请查看更新的代码片段!

function setPrice() {
  if (document.getElementById('3').checked) {
    document.getElementById('price').innerHTML = "19,99€";
  } else if (document.getElementById('12').checked) {
    document.getElementById('price').innerHTML = "<<<";
  } else if (document.getElementById('24').checked) {
    document.getElementById('price').innerHTML = "xxx";
  }
}

setPrice();

<div id="variant">
  <label><input type="radio" name="toggle" id="3" onClick="setPrice();"><span>A</span></label>
  <label><input type="radio" name="toggle" id="12" onClick="setPrice();" checked="checked"><span>B</span></label>
  <label><input type="radio" name="toggle" id="24" onClick="setPrice();"><span>C</span></label>
</div>
<br>
<div id="price"></div>