Python 扰码器程序

Question

该程序将句子中的单词打乱。规则是:- 第一个和最后一个字母保持不变- 单词末尾的标点符号保持不变- 单词中的标点符号像中间字母一样被打乱

我的问题是，如果我在单词末尾有多个标点符号，它不会打乱它。

例如)测试!!!应该是类似 t!ste!nig! 的东西或者测试!测试!尼格!但不是 tstenig!!!

我该如何解决这个问题？

import random
import string

original_text = input("Enter your text: ").split(' ')
seed = int(input("Enter a seed (0 for random): "))

punctuation = []
for c in string.punctuation:
    punctuation.append(c)

if seed is not 0:
    random.seed(seed)

randomized_list = []

def scramble_word(word):
    alpha = word[0]
    end_punctuation = ''

    if word[-1] in punctuation:
        x = -1
        while word[x] in punctuation:
            end_punctuation += word[x]
            x -= 1
        omega = word[x]
        middle = word[1: x]
    else:
        omega = word[-1]
        middle = word[1:-1]
        end_punctuation = ""
    middle_list = list(middle)
    random.shuffle(middle_list)
    shuffled_text = "".join(middle_list)
    new_words = alpha + shuffled_text + omega + end_punctuation
    return new_words
for item in original_text:
    if len(item) <= 3:
        randomized_list.append(item)
    else:
        randomized_list.append(scramble_word(item))
new_words = " ".join(randomized_list)
print(new_words)

Answer 1

问题是你没有在随机播放中添加标点符号；请参阅下面修改后的两行:

if word[-1] in punctuation:
    x = -1
    while word[x] in punctuation:
        end_punctuation += word[x]
        x -= 1
    omega = word[x]
    middle = word[1: x] + end_punctuation[1:] # Include all except the final character
    end_punctuation = end_punctuation[0]  # Just use the final character
else:
    omega = word[-1]
    middle = word[1:-1]
    end_punctuation = ""

这对我有用:

In [63]: scramble_word('hello!?$')
Out[63]: 'hle?l!o$'

In [64]: scramble_word('hello!?$')
Out[64]: 'h?!ello$'

In [65]: scramble_word('hello!?$')
Out[65]: 'hlel!?o$'

In [66]: scramble_word('hello!')
Out[66]: 'hlleo!'

In [67]: scramble_word('hello!')
Out[67]: 'hello!'

In [68]: scramble_word('hello!')
Out[68]: 'hlleo!'

In [69]: scramble_word('hello')
Out[69]: 'hlelo'

顺便说一下，您不需要punctuation 变量； string.punctuation 中的 word[x] 的工作原理相同。