php - 读取并解析制表符分隔文件 PHP

Question

我编写了这个 Python 脚本来读取制表符分隔的文件，并将以 '\t' 开头的行的值放入 array 中。我为此使用的代码:

import sys
from collections import OrderedDict
import json
import os   

file = sys.argv[1]

f = open(file, 'r')
direc = '/dir/to/JSONs/'
fileJSON = sys.argv[1]+'.json'

key1 = OrderedDict()
summary_data = []
full_path = os.path.join(direc,fileJSON)

Read = True 
for line in f:
        if line.startswith("#"):
            Read = True

        elif line.startswith('\tC'):
            Read= True

        elif line.startswith('\t') and Read == True:
            summary = line.strip().split('\t')
            key1[summary[1]]=int(summary[0])
            Read = True    

summary_data.append(key1)
data = json.dumps(summary_data)
with open(full_path, 'w') as datafile:
    datafile.write(data)
print(data)

我正在解析的数据:

# BUSCO was run in mode: genome

    C:98.0%[S:97.0%,D:1.0%],F:0.5%,M:1.5%,n:1440

    1411    Complete BUSCOs (C)
    1397    Complete and single-copy BUSCOs (S)
    14  Complete and duplicated BUSCOs (D)
    7   Fragmented BUSCOs (F)
    22  Missing BUSCOs (M)
    1440    Total BUSCO groups searched

但是，我需要 PHP 中的这段代码..我已经设法在 PHP 中打开该文件并阅读此内容!有人可以帮我吗？

Answer 1

我没有明白 Read 变量的意义 - 它在您的代码中始终为 True，最后一个 'elif' 语句就足够了。以下是脚本的 php 版本

<?php
    $fileName = $argv[1];
    $dir = '/dir/to/JSONs/';
    $fullPath = $dir . $fileName . '.json';

    $data = [];
    $output = fopen($fileName, 'r');
    while (($line = fgets($output)) !== false) {
        if ($line[0] == "\t") {
            $summary = explode("\t", trim($line));
            if (count($summary) > 1) {
                $data[$summary[1]] = (int)$summary[0];
            }
        }
    }

    $strData = json_encode([$data]);
    $input = fopen($fullPath, 'w+');
    fwrite($input, $strData);
    echo $strData;