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javascript - 如何构造 python 对象以便它们能够很好地 JSONify?

转载 作者:行者123 更新时间:2023-12-01 03:24:39 24 4
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我对 python 相当陌生,来自 js。

我正在尝试使用 json 在客户端和服务器之间进行通信,但我无法理解 python (tornado) 中与对象属性等效的简单 jsonifyable 是什么。下面的对象创建代码取自此 SO 答案( https://stackoverflow.com/a/2827726/4808079 ),会引发一些错误。

class MainHandler(tornado.web.RequestHandler):
def post(self):
#getting and parsing json works as expected
args = json.loads(self.request.body.decode())

#can't seem to figure out how to make this jsonify well
out = []
for num in range(0,5):
addMe = type('', (), {})
addMe.value = num
addMe.square = num * num
out.append(addMe)

self.write(json.dumps(out))

控制台错误:

Traceback (most recent call last):
File "/Library/Python/2.7/site-packages/tornado/web.py", line 1509, in _execute
result = method(*self.path_args, **self.path_kwargs)
File "test_tornado.py", line 43, in post
self.write(json.dumps(out))
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/json/__init__.py", line 243, in dumps
return _default_encoder.encode(obj)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/json/encoder.py", line 207, in encode
chunks = self.iterencode(o, _one_shot=True)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/json/encoder.py", line 270, in iterencode
return _iterencode(o, 0)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/json/encoder.py", line 184, in default
raise TypeError(repr(o) + " is not JSON serializable")
TypeError: <class '__main__.'> is not JSON serializable

与我上面尝试的等效内容在 JavaScript 中是这样的:

var out = []
for(var num = 0; num < 5; num++) {
var addMe = {};
addMe.value = num;
addMe.square = num*num;
out.push(addMe);
}
return JSON.stringify(out);

我应该如何在 Python 中构造一个对象,以便它能够很好地 JSON 化?

最佳答案

您可以开箱即用地对字典进行编码:

addMe = {
'value': num,
'square': num * num
}

关于javascript - 如何构造 python 对象以便它们能够很好地 JSONify?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/44914168/

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