Python 逻辑 Black Jack sim

Question

我不知道我哪里做错了，但打印总是可能胜利 100%

import random

设置牌组并查看单场比赛的分数

def singleGame():
    cardsVal = [11, 2, 3, 4, 5, 6, 7, 8, 9, 10, 10, 10, 10] # deck of cards
    onhandScore = 17 # score on hand
    cardNumber = pickOneCard()
    newCardValue = cardsVal[cardNumber - 1]
    onhandScore = onhandScore + newCardValue

检查是否获胜、失败或平局

if onhandScore > 21:
    result = 1
elif onhandScore == 21:
    result = 0
else:
    result = -1

return result

从 13 张牌中选择一张并返回其牌号

def pickOneCard():
    return random.randint(1, 13)

检查 n 次模拟并打印结果

def multipleGames(n):

记录分数

defeat = 0;
certainVictory = 0;
likelyVictory = 0;

一一模拟n场比赛

for i in range(n):
    result = singleGame()

检查分数并存储值

if result == 1:
    defeat += 1
elif result == 0:
    certainVictory += 1
else:
    likelyVictory += 1

计算总百分比

totalPer = (defeat + certainVictory + likelyVictory)
defeatPer = float("{0:.2f}".format(defeat * 100/ totalPer))
certainVictoryPer = float("{0:.2f}".format(certainVictory * 100/ totalPer))
likelyVictoryPer = 100 - defeatPer - certainVictoryPer

打印结果

print 'Defeats: ',defeatPer,'%'
print 'Certain victories: ',certainVictoryPer,'%'
print 'Likely victories: ',likelyVictoryPer,'%'

100,000 个游戏的模拟代码

multipleGames(100000)

Answer 1

检查您的缩进以检查胜利、失败或平局。您的 return 语句应该位于 if 语句之外，如下所示。

if onhandScore > 21:
    result = 1
elif onhandScore == 21:
    result = 0
else:
    result = -1

return result

因此，只有在到达 else 情况时才会返回整数值。否则，该函数默认返回 None。现在，当我们到达这里时。

if result == 1:
    defeat += 1
elif result == 0:
    certainVictory += 1
else:
    likelyVictory += 1

None 不等于 1 或 0，因此它到达 else，并且当它到达 >return -1 这也为 likelyVictory 添加了 1。