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python - Django 'OneToOneField' 对象没有属性 'id'

转载 作者:行者123 更新时间:2023-12-01 03:19:10 46 4
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我尝试根据默认 User 对象的 id 创建编码的 id 字段,但收到以下错误(完整跟踪):

Traceback (most recent call last):
File "manage.py", line 22, in <module>
execute_from_command_line(sys.argv)
File "/Users/default_user/Documents/pumac3/venv/lib/python2.7/site-packages/django/core/management/__init__.py", line 367, in execute_from_command_line
utility.execute()
File "/Users/default_user/Documents/pumac3/venv/lib/python2.7/site-packages/django/core/management/__init__.py", line 341, in execute
django.setup()
File "/Users/default_user/Documents/pumac3/venv/lib/python2.7/site-packages/django/__init__.py", line 27, in setup
apps.populate(settings.INSTALLED_APPS)
File "/Users/default_user/Documents/pumac3/venv/lib/python2.7/site-packages/django/apps/registry.py", line 108, in populate
app_config.import_models(all_models)
File "/Users/default_user/Documents/pumac3/venv/lib/python2.7/site-packages/django/apps/config.py", line 199, in import_models
self.models_module = import_module(models_module_name)
File "/usr/local/Cellar/python/2.7.12/Frameworks/Python.framework/Versions/2.7/lib/python2.7/importlib/__init__.py", line 37, in import_module
__import__(name)
File "/Users/default_user/Documents/pumac3/pumac3/registration/models.py", line 52, in <module>
class Coach(models.Model):
File "/Users/default_user/Documents/pumac3/pumac3/registration/models.py", line 61, in Coach
user_id = models.CharField(max_length=254, default=urlsafe_base64_encode(force_bytes(user.id)))
AttributeError: 'OneToOneField' object has no attribute 'id'

我的 models.py 中的 Coach 模型如下所示:

class Coach(models.Model):
user = models.OneToOneField(User, unique=True)

# Sets default user values
user.is_active = False

# For account activation and password resetting
user_timestamp = models.IntegerField(default=int(time.time()))
user_id = models.CharField(max_length=254, default=urlsafe_base64_encode(force_bytes(user.id)))
user_token = models.CharField(max_length=254, default=default_token_generator.make_token(user))

name = models.CharField(max_length=100)
phone_number = models.CharField(max_length=20)

class Meta:
verbose_name_plural = "Coaches"
ordering = ['name']

def __unicode__(self):
"""Returns the name of the coach if has name, otherwise returns email."""
if self.name:
return self.name
else:
return self.user.email

def update_token(self):
"""Updates the user_token and timestamp for password reset or invalid activation"""
self.user_timestamp = int(time.time())
self.user_token = default_token_generator.make_token(user)
self.save()

@staticmethod
def is_coach(user):
return hasattr(user, 'coach')

@staticmethod
def authorized(user):
"""Returns a queryset of Coach objects the user can view and modify."""
if hasattr(user, 'coach'):
# check that the user is a coach
return user.coach

@staticmethod
def authorized_organizations(user):
"""
Returns a queryset of organizations the user can view and modify.
"""
if hasattr(user, 'coach'):
return user.coach.organizations.all()

我尝试过查看与我的类似的其他问题,但是该人指定了主键,因此 Django 没有创建默认的 id 字段。但是,我没有在 Coach 模型中执行此操作,即使是这样,Django 默认 User 模型不应该包含 id 属性吗?

我怀疑问题在于 id 字段仅在实际创建 User 实例之后才存在,因此我无法为 user_id< 创建值。在创建 User 类的实例后,我是否应该在 models.py 之外实例化该值?

最佳答案

您不能在类的顶层代码中使用实例数据。在代码运行时(导入时),还没有实例。如果要使用计算数据初始化实例,请覆盖该类的 __init__ 方法。

关于python - Django 'OneToOneField' 对象没有属性 'id',我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/42106898/

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